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Tresset [83]
3 years ago
7

Casey Electronics has a piece of machinery that costs $300,000 and is expected to have a useful life of 6 years or 40,000 hours.

Residual value is expected to be $50,000.
Using the units-of-production method, what is depreciation expense for the first year assuming it was used 6,000 hours?

A. I DON'T KNOW YET
B. $41,667
C. $81,000
D. $70,000
Business
1 answer:
kozerog [31]3 years ago
4 0

Answer:

None of the given options.

Depreciation expense for year 1 would be $37,500.

Explanation:

Cost = $400,000

Residual value = $50,000  

Expected hours = 40,000

Working hours (year 1) = 6,000 hours  

Now,  

Depreciation per hour = \frac{Cost-Residual Value}{Expected hours}  

Depreciation per hour = \frac{300,000 - 50,000}{40,000}  

Depreciation per hour = \frac{250,000}{40,000}  

Depreciation per hour = $6.25

Depreciation expense (year 1) = Depreciation per hour × Working hours (year 1)

Depreciation expense (year 1) = $6.25 × 6,000

Depreciation expense (year 1) = $37,500

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Examples of bad faith include undue delay in handling claims, inadequate investigation, refusal to defend a lawsuit, threats against an insured, refusing to make a reasonable settlement offer, or making unreasonable interpretations of an insurance policy.

Explanation:

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3 years ago
If the profit-maximizing markup factor in a 3-firm cournot oligopoly is 2, what is the corresponding market elasticity of demand
AVprozaik [17]

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Where do banks get money to lend to borrowers?
PolarNik [594]

Answer:

They create the money they lend to borrowers.

Explanation:

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7 0
3 years ago
How much money should be deposited annually in a bank account for five years if you wish to withdraw ​$5 comma 500 each year for
Zarrin [17]

Answer:

The initial deposit should be $ 25.46

Explanation:

The Annuity formula is

P=R [1−(1+i)^-n/i]⋅(1+i)

Where

P= Initial deposit

R=Regular Withdraw amount

i=Interest rate

n=Number of years/periods

After entering corresponding values in the formula we get $25.46

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6 0
3 years ago
The following two graphs show the markets for smartphones in Sweden and Norway. Use the graphs to answer the questions that foll
zalisa [80]

Answer:

Assume there are no transportation costs. With trade, the price of $22.5 brings about balance in exports and imports. At this price, 600 smartphones are traded. With trade, Sweden produces 900 smartphones and consumes 300 smartphones, and Norway produces 300 smartphones and consumes 900 smartphones.

Now suppose the per-unit transportation cost from Sweden to Norway is $5. With trade, the transportation cost changes the price of smartphones in Sweden to $25 and in Norway to $25. Sweden will produce 800 smartphones and consume 400 smartphones, thus exporting 400 smartphones. Norway will produce 400 smartphones and consume 800 smartphones, thus importing 400 smartphones.

Explanation:

With no transportation costs, Sweden shall export smartphones and Norway shall import smartphones because the market price is lower in Sweden than in Norway.

The demand and supply functions for smartphones in Sweden, derived from the given values, are:

Q_{D} = 1200 - 40P\\

Q_{S} = 40P

The export supply (ES) equation is:

ES = Q_{S} - Q_{D}

ES = 40P - (1200 - 40P)

ES = 80P - 1200

The demand and supply functions for smartphones in Norway, derived from the given values, are:

Q_{D} = 1800 - 40P

Q_{S} = 40P - 600

The import demand (ID) equation is:

ID = Q_{D} - Q_{S}

ID = 1800 - 40P - (40P - 600)

ID = 2400 - 80P

The equilibrium price and quantity traded is determined where ES = ID.

80P - 1200 = 2400 - 80P

This simplifies to P = 22.5

Q = 2400 - 80(22.5) = 600

Next, a transaction cost of $5 per unit is imposed from Sweden to Norway. This changes the ES function as follows.

New ES = 80(P - 5) - 1200

New ES = 80P - 1600

The new equilibrium is where New ES = MD.

80P - 1600 = 2400 - 80P

This simplifies to P = 25

Q = 80(25) - 1600 = 400

7 0
3 years ago
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