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amid [387]
3 years ago
13

When a number x is multiplied by 6, the result is 3/8 . What is the value of x?

Mathematics
1 answer:
JulsSmile [24]3 years ago
7 0
1/16 * 6 = 6/16 or reduced to 3/8
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2 years ago
) Three sides of a quadrilateral are the same length, q. The length of the fourth side is 7 inches.
Kruka [31]

Answer:

q=(40-7)/3 or simplified q=11

Step-by-step explanation:

So we know that the perimeter is 40 inches and one of the sides is 7 so logically we do 40-7 to get the length of the three remaining sides combined. Then to find the length q, we have to divide that answer by 3 because the three sides have the same length or (40-7)/3, which simplified is 11, so the length of the side is 11 inches and the expression is q=(40-7)/3.

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What is 485 times 34
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A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5
lara [203]

Answer:

7.3% of the bearings produced will not be acceptable

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 0.499, \sigma = 0.002

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.

So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.

Larger than 0.504

1 subtracted by the pvalue of Z when X = 0.504.

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.504 - 0.494}{0.002}

Z = 2.5

Z = 2.5 has a pvalue of 0.9938

1 - 0.9938= 0.0062

Smaller than 0.496

pvalue of Z when X = -1.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.496 - 0.494}{0.002}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.0668 + 0.0062 = 0.073

7.3% of the bearings produced will not be acceptable

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3 years ago
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