Procedure:
1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)
Solution
1) the number of teams of four members that can be formed are:
10*9*8*7 / (4*3*2*1) = 210
2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls
Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6
Number of different teams with 2 boys and 2 girls = 15 * 6 = 90
3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:
90/210 = 3/7
parallel means "same slope (m)"
m =
= 
Now, input the point (0, 0) and the slope
into the Point-Slope formula:
y - y₁ = m(x - x₁)
y - 0 =
(x - 0)
y = 
3y = -5x <em>multiplied both sides by 3</em>
0 = -5x - 3y <em>subtracted 3y from both sides</em>
Answer: C
Assuming that the figures given are square such that the scale factor between them is equal to 28/8 which can be further simplified into 7/2. The ratio of the perimeter is also equal to this value, 7/2. However, the ratio of the areas is equal to the square of this value giving us an answer of 49/4.
Answer:
The given relation is not a function
Step-by-step explanation:
- The relation becomes a function if every x-value has only one y-value
- A function is a relation in which each input (x) has only one output (y)
<em>To test the graph is a function or not, draw a vertical line intersects the graph in different positions, if the line cuts the graph in just one point in all positions, then the graph represents a function.</em>
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From the given figure
∵ The endpoint of the diameter of the semi-circle are (0, -2), (0, 2)
→ The x-coordinate = 0 has two values of y = -2, 2
∴ At x = 0, y = -2 and 2
∴ Not every x has only one y
∴ The given relation is not a function
<em>If you draw a vertical line intersects the semi-circle in different positions, it will intersect the semi-circle in 2 points, So the graph does not represent a function </em>