Answer:290
Step-by-step explanation:
Y=33x + 104 -(45+66).......
452,165.36 ? That should be the answer lol
In the study the total number of males was 739 and the total number of all employees was 1501. The men who felt stressed or tensed out during work were 244 and those that never felt stressed out were 495.
Assuming that, A= Employed adults was male and B= Employed adult felt tense or stress out at work.
Then , P(A/B) = P(A∩B)/ P(B)
P(B) is the probability of having a male.
P(B) = 739/1501
P(A∩B) is the probability of a man being stressed or tensed out at work.
and P(A∩B) = 244/ 1501
Hence, P(A/B) =(244/1501)/ (739/1501)
= 244/739
= 0.3302.
Thus, the probability that the employed work felt tense or stress at work given that the employed employee was male is 0.3302
Answer:
61/100 61/1
Step-by-step explanation:
