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4 years ago

Solve the system of equations using Gaussian elimination or Gauss-Jordan elimination. 2x + 6y = 6 3x + 9y = 9

Mathematics

1 answer:

Elan Coil [88]4 years ago

5 0

The answer is x=-3/40 :)

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A population of deer inside a park has a carrying capacity of 200 and a growth rate of 3%. If the initial population is 80 deer,

otez555 [7]

Answer:

The population of deer at any given time = 200(e^0.03t) ÷ (1.5 + (e^0.03t))

Step-by-step explanation:

This is an example of logistic equation on population growth

carrying capacity, k = 200

Rate, r = 3% = 0.03

Initial Population, P1 = 80

P(t) =?

P(t) = (P1 (k)(e^rt)) ÷ (k- P1 + P1(e^rt))

P(t) = (80 (200)(e^0.03t)) ÷ (200 - 80 + 80(e^0.03t))

= (16000(e^0.03t)) ÷ (120 + 80(e^0.03t))

= 200(e^0.03t) ÷ (1.5 + (e^0.03t))

8 0

3 years ago

In the figure, qj= 2x+100 and sj=6x+52 what is sj ?

Phoenix [80]

Answer:

124

Step-by-step explanation:

2x+100=6x+52

solve for variable x = 12

plug it in

2(12)+100

sj= 124

5 0

4 years ago

A high school is having a pancake breakfast fundraiser. They have 4 packages of pancake mix that each feed 120 people. The funct

horrorfan [7]

Answer:

$1 \leqslant no \: packages = m \leqslant 4$

then

$x = no \: members \: cooking \: team \leqslant n$

Step-by-step explanation:

Imagine the space they need to host at least 120 people so they could open the second package and finish before noon

5 0

4 years ago

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

maxonik [38]

Answer:

5.0 ft-lbf

Step-by-step explanation:

The force is

$F = \dfrac{9}{6^x}$

This force is not a constant force. For a non-constant force, the work done, <em>W</em>, is

$W = \int\limits^{x_2}_{x_1} {F(x)} \, dx$

with $x_1$ and $x_2$ the initial and final displacements respectively.

From the question, $x_1 =0$ and $x_2 = 12$ .

Then

$W = \int\limits^{12}_0 {\dfrac{9}{6^x}} \, dx$

Evaluating the indefinite integral,

$\int\limits \dfrac{9}{6^x} \, dx =9 \int\limits\!\left(\frac{1}{6}\right)^x \, dx$

From the rules of integration,

$\int\limits a^x\, dx = \dfrac{a^x}{\ln a}$

$9 \int\limits \left(\frac{1}{6}\right)^x \, dx = 9\times\dfrac{(1/6)^x}{\ln(1/6)} = -5.0229\left(\dfrac{1}{6}\right)^x$

Returning the limits,

$\left.-5.0229\left(\dfrac{1}{6}\right)^x\right|^{12}_0 = -5.0229(0.1667^{12} - 0.1667^0) = 5.0229 \approx 5.0 \text{ ft-lbf}$

4 0

3 years ago

Can someone plss help me (middle school 7th grade) I dont this

AVprozaik [17]

Answer:

what is it over?

Step-by-step explanation:

you have to be more specific

4 0

3 years ago