I need help pls someone

For what power of q is its value 1?

DedPeter [7]

Answer:

0, for q ≠ 0 and q ≠ 1

Step-by-step explanation:

Assuming q ≠ 0, you want to find the value of x such that ...

q^x = 1

This is solved using logarithms.

__

x·log(q) = log(1) = 0

The zero product rule tells us this will have two solutions:

x = 0

log(q) = 0 ⇒ q = 1

If q is not 0 or 1, then its value is 1 when raised to the 0 power. If q is 1, then its value will be 1 when raised to any power.

_____

Additional comment

The applicable rule of logarithms is ...

log(a^b) = b·log(a)

4 0

1 year ago

If AE=6x-55 and EC=3x-16, find DB. (Hint: Find x first and then substitute.)

erica [24]

Given:

Given that ABCD is a rectangle.

The diagonals of the rectangle are AC and DB.

The length of AE is (6x -55)

The length of EC is (3x - 16)

We need to determine the length of the diagonal DB.

Value of x:

The value of x can be determined by equating AE and EC

Thus, we have;

$AE=EC$

Substituting the values, we get;

$6x-55=3x-16$

$3x-55=-16$

$3x=39$

$x=13$

Thus, the value of x is 13.

Length of AC:

Length of AE = $6(13)-55=78-55=23$

Length of EC = $3(13)-16=39-16=23$

Thus, the length of AC can be determined by adding the lengths of AE and EC.

Thus, we have;

$AC=AE+EC$

$AC=23+23$

$AC=46$

Thus, the length of AC is 46.

Length of DB:

Since, the diagonals AC and DB are perpendicular to each other, then their lengths are congruent.

Hence, we have;

$AC=DB$

$46=DB$

Thus, the length of DB is 46.

6 0

2 years ago

Please help me I'll give you a brainliest

astraxan [27]

Okay try to round the whole number and see if you can solve that should help you

7 0

2 years ago

20) Your goal is to earn at least $234.50 this week. If you earn $8.00 per hour plus a bonus amount of $130.50, how many hours d

NISA [10]

Answer:

13

Step-by-step explanation:

243.50 - 130.50 = 104

104 ÷ 8 = 13

6 0

3 years ago

ANSWER ALL 5 PARTS.

N76 [4]

A function $f$ from a set A to a set B is defined as a relation that assings to each element $x$ in the set A exactly one element $y$ in the set B. The set A is called the domain of the function while the set B is the range. So we have five statements and need to find some functions. Melissa decides to reserve a patch in her vegetable garden for growing bell peppers. If each side of the tomato patch is $x$ feet, then we have a square patch as shown in the Figure below.

1.a) Write the function Wa(x) representing the width of the bell pepper patch.

We know that she wants its width to be half the width of the tomato patch. Let $x$ be the width of the tomato patch, then the function that matches this statement is:

$\boxed{Wa(x)=\frac{x}{2}}$

1.b) Write the function La(x) representing the length of the bell pepper patch.

In this case Melissa wants its length to exceed the length of the tomato patch by 2 feet. To do this we enlarge the length of the tomato patch 2 feet. Therefore the function is the following:

 $\boxed{La(x)=x+2}$

2. Area of the bell pepper patch in terms of x.

Given that the bell pepper patch is a rectangle, then the area of a rectangle is the product of the length and width. So:

 $A=(\frac{x}{2})(x+2) \\ \\ \therefore \boxed{A=\frac{x(x+2)}{2}}$

3. Combined area of the tomato patch and the bell pepper patch.

This function is the sum of both the area of the tomato patch and the bell pepper patch. So:

 $Aar(x)=x^{2}+\frac{x(x+2)}{2} \rightarrow Aar(x)=x^{2}+ \frac{x^{2}}{2}+x \rightarrow Aar(x)=\frac{3x^{2}}{2}+x \\ \\ \therefore \boxed{Aar(x)=\frac{x(3x+2)}{2}}$

4. Write the function Aa(x) for the remaining planting area in the garden.

The remaining planting area in the garden are the rectangles in red. So we need to subtract the width of the bell pepper patch from the width of the tomato patch and multiply it by 2. In mathematical language this is given by:

 $Aa(x)=2(x-\frac{x}{2}) \rightarrow Aa(x)=x$

5. Find the area of the remaining space in the garden after planting tomatoes and bell peppers.

Given that Melissa wants the area of the bell pepper patch to be 31.5 square feet, then it is true that:

 $31.5=\frac{x(x+2)}{2} \rightarrow x^{2}+2x-64=0 \\ \\ solving \ for \ x: \\ x=7.06$

Therefore the area of the remaining space is:

 $\boxed{Aa(7.06)=7.06ft^{2}}$

6 0

3 years ago