Answer:
4107 cells
Step-by-step explanation:
From the question, we have the following values:
Day 1 : 113 cells
Number of cells increases by day by 82%
Hence,
Day 2
113 × 82% = 92.66cells
Hence, Total number of bacteria cells for Day 2 = 113 + 92.66 = 205.66cells
Day 3
205.66 × 82% = 168.6412 cells
Hence, Total number of bacteria cells for Day 3 = 168.6412 + 205.66 = 374.3012 cells
Day 4
374.3012 × 82% = 306.926984 cells
Hence, Total number of bacteria cells for Day 4 = 306.926984 + 374.3012 = 681.228184 cells
Day 5
681.228184 × 82% = 558.60711088 cells
Hence, Total number of bacteria cells for Day 5 = 558.60711088 + 681.228184 = 1239.8352949 cells
Day 6
1239.8352949 × 82% = 1016.6649418 cells
Hence, Total number of bacteria cells for Day 5 = 1016.6649418 + 1239.8352949 = 2256.5002367 cells
Day 7
2256.5002367 × 82% = 1850.3301941 cells
Hence, Total number of bacteria cells for Day 7 = 1850.3301941 + 2256.5002367 = 4106.8304308 cells
Approximately to nearest whole number, the total number of bacteria cells that would be present after 7 days = 4107 cells
