A group of friends wants to go to the amusement park. They have no more than $320 to spend on parking and admission. Parking is $9.25, and tickets cost $28.25 per person, including tax. Write and solve an inequality which can be used to determine p, the number of people who can go to the amusement park.
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Please, give me some minutes to take over your question
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They have no more than $320 to spend on parking and admission
320 ≥ 9.25 + 28.25*p
9.25 + 28.25*p ≤ 320
320- 9.25 ≥ 28.25*p
310.75/28.25 ≥ p
p ≤ 11
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Answer
The number of people who can go to the amusement park can be a maximum of 11 people (less than or equal to 11).
Answer:It should be 49.365
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
There's 3 colors on the circle and they're all divided equally so it will be 1/3 of a chance
Answer:
The correct locations are;
Part to part ratio is 3 cats to 5 dogs
Whole to part ratio is 10 pets to 2 rabbits
Part to whole ratio is 5 dogs to 10 pets
Step-by-step explanation:
The given information are;
The number of cats Jim has = 3
The number of dogs Jim has = 5
The number of rabbit Jim has = 2
The total number of pets Jim has = 3 + 5 + 2 = 10 pets
Therefore;
The fraction of the pets that are cats = 3/10
The fraction of the pets that are dogs = 5/10
The fraction of the pets that are rabbits= 2/10
Therefore we have;
Part to part ratio = 3/10 cats to 5/10 dogs = 3 cats to 5 dogs
Whole to part ratio → 10 pets to 2 rabbits
Part to whole ratio → 5 dogs to 10 pets.
Answer:
70
Step-by-step explanation:
In this problem, 27 adults conduct a survey.
In the results of the survey, it is found that 35% of the adults are concerned with poverty.
If we call:
x = number of adults surveyed
y = adults concerned with poverty
This means that we can write the following relationship:
(1)
where 
represents the percentage of adults concerned with poverty, rewritten in decimal form (
)
Later, we are told that 200 adults are surveyed, so now we have
x = 200
So substituting into eq(1) we can find how many of these adults are concerned with poverty:
