Answer:
2 sqrt(3) = n
k = 4 sqrt(3)
Step-by-step explanation:
We know that cos 30 = adjacent/ hypotenuse
cos 30 = 6 /k
Multiply each side by k
k cos 30 = 6k * k
k cos 30 = 6
Divide each side by cos 30
k cos 30/ cos 30 = 6/ cos 30
k = 6 / cos 30
k = 6/ (sqrt(3)/2)
k =12 / sqrt(3)
We cannot leave the sqrt in the denominator
k = 12 / sqrt(3) * sqrt(3)/sqrt(3)
k = 12 sqrt(3)/3
k = 4 sqrt(3)
We know tan 30 = opposite/adjacent
tan 30 = n/6
Multiply each side by 6
6 tan 30 = n
6 * (sqrt(3)/3) = n
6/3 * sqrt(3) = n
2 sqrt(3) = n
Answer:
W=28
Step-by-step explanation:
(W/4)-4=3
(W/4)=7
W=28
In other terms, the Transitive Property states that if ∠a = ∠b and ∠b = ∠c, then ∠a = ∠c. So, if ∠XYZ = ∠AOB and ∠AOB = ∠WYT, then ∠XYZ = ∠WYT. The correct answer here would be B.
Answer:
the answer to the question is -75
