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PolarNik [594]
3 years ago
14

2. Find the probability that an event E will not occur if

Mathematics
1 answer:
Monica [59]3 years ago
3 0

Answer:

Step-by-step explanation:

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Blake collects coins. He collected a total of 225 coins. If ​68% of the coins he collected were​ foreign, how many other coins d
Bingel [31]

Answer: 72

Step-by-step explanation:

convert 68% to decimal:

0.68

Multiply by 225

0.68*225

= 153

Subtract:

225-153=
72

8 0
2 years ago
A carpool contains three kindergartners and five first-graders. if two children are ill, find the probability that at least one
sladkih [1.3K]

Solution: We are given that there are three kindergartners and five first-graders.

We have to find the probability that at least one of them is a kindergartner.

We know that:

P(at least one kindergartner) = 1 - P(no kindergartner) = 1 - P(all first-graders)

Now, P(all first-graders)=\frac{5}{8} \times \frac{4}{7}=\frac{5}{14}

Therefore, P(at least one kindergartner) =1-\frac{5}{14}

                                                                   =\frac{14-5}{14}=\frac{9}{14}=0.643                                      

3 0
3 years ago
Which of the following is an equivalent expression to the expression a 1/3/ a /14
denis23 [38]

A. a^1/12

When dividing two exponents with the same base, subtract the denominator exponent from the numerator's exponent.

the difference is the value of the new exponent with the same base.

3 0
2 years ago
True or False<br> x=11.25<br> True<br> False
nata0808 [166]

Answer:

False

Step-by-step explanation:

6x+2x+8=180

8x+8=180

8x=172

x=172/8

x=21.5

5 0
3 years ago
According to the Venn diagram, if P(A)=0.3 and P(B)= 0.35, what is P(A B)? <br>PLEASE HELP MEEE!!​
STALIN [3.7K]

Answer:

A. P(A\cup B)=0.55

Step-by-step explanation:

From the Venn diagram,

P(A) = 0.3, P(B) = 0.35, and P(A\cap B) = 0.10

Therefore, from the rule of Addition of probabilities,

P(A\cup B )=P(A)+P(B)-P(A\cap B)\\P(A\cup B )=0.3+0.35-0.10\\P(A\cup B )=0.55

Therefore, option A is correct.

3 0
3 years ago
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