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Luba_88 [7]
3 years ago
8

Slope is 2, and (3,8) is on the line. Please help :(

Mathematics
1 answer:
MaRussiya [10]3 years ago
5 0
Are you trying to write an equation?

y-8=2(x-3)
y=2x-6+8

y=2x+2
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aniked [119]
The answer is -1.5. Hope this helps
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3 years ago
Find the sum of the interior angle measure of a regular polygon with 20 sides
AleksAgata [21]

Answer:

3240°

Step-by-step explanation:

For a regular icosagon,

sum of interior angles measure=180(n-2)°

180(20-2)

180(18)=3240°

8 0
3 years ago
Need help with Calculus 1 inverse trig functions
lidiya [134]

Answer:

\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}

Step-by-step explanation:

<u>The Derivative of a Function</u>

The derivative of f, also known as the instantaneous rate of change, or the slope of the tangent line to the graph of f, can be computed by the definition formula

\displaystyle f'(x)=\lim\limits_{\Delta x \rightarrow 0}\frac{f(x+\Delta x)-f(x)}{\Delta x}

There are tables where the derivative of all known functions are provided for an easy calculation of specific functions.

The derivative of the inverse tangent is given as

\displaystyle (tan^{-1}u)'=\frac{u'}{1+u^2}

Where u is a function of x as provided:

y=3tan^{-1}(x+\sqrt{1+x^2})

If we set

u=(x+\sqrt{1+x^2})

Then

\displaystyle u'=1+\frac{2x}{2\sqrt{1+x^2}}

\displaystyle u'=1+\frac{x}{\sqrt{1+x^2}}

Taking the derivative of y

y'=3[tan^{-1}(x+\sqrt{1+x^2})]'

Using the change of variables

\displaystyle y'=3[tan^{-1}u]'=3\frac{u'}{1+u^2}

\displaystyle y'=3\frac{u'}{1+u^2}=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+(x+\sqrt{1+x^2})^2}

Operating

\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+x^2+2x\sqrt{1+x^2}+1+x^2}

\boxed{\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}}

8 0
3 years ago
Eva decorated cupcakes with pound of red jelly beans and pound of blue jelly beans. She says that she used pound of jelly beans
nikklg [1K]

Answer:

No, her statement is not reasonable. This is because, she refused to acknowledge the fact that she used a pound of Blue Jelly during the decoration of the cake.

<em>Skipping this information makes is dangerous for others who might not be aware of the Blue Jelly and eat the cupcakes thereby causing them problems (Maybe, they are allergic to Blue Jelly)</em>

Step-by-step explanation:

4 0
3 years ago
Find the 16th term , given the first term and the common difference. a1=8 and d=3
sattari [20]
By using the formula for arithmetic sequence, the 16th term of the progression can be obtained. Given A1=8 and d=3,
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A16=8+(16-1)(3)
A16=53
8 0
3 years ago
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