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gogolik [260]
3 years ago
8

Malia has her $ 10.00 allowence to spend at the fall carnival. She decides to order two ice cream cones for herself and her sist

er. What is the resulting change in Malia's allowence?
Mathematics
2 answers:
Ierofanga [76]3 years ago
7 0

Answer:

Step-by-step explanation:

Ahat [919]3 years ago
4 0

Answer:

Malia's allowance changed from $10.00 to $(10-2x) after buying ice cream cones.

Step-by-step explanation:

We are given the following information:

Malia's allowance to spend at carnival = $10.00

Ice cream ordered by her = 2

Let x dollars be the cost of one ice cream cone.

Total money spent on ice creams = 2x

Formula:

\text{Change in Malia's allowance} = \text{Total allowance} - \text{Money spent on ice cream cones}\\= 10 - 2x

Thus, Malia's allowance changed from $10.00 to $(10-2x) after buying ice cream cones.

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Ravi bought 50kg rice at the rate it tk40 per kg and sold it at the rate of tk44 per kg. What is the amount of profit or loss?
ololo11 [35]

Here is your Answer

Step-by-step explanation:

Ravi bought rice = 50kg

Rate it =40kg

Sold it at the rate = = 44kg

<h3>Answer: -34</h3><h2 /><h2 /><h2>Mark me as brainlist and give me 20 thx pls</h2>
6 0
2 years ago
Bob decides he wants to make guitars and sell them online. He makes and sells Gibson Explorer’s and Gibson Flying V’s. He can ma
lozanna [386]
Okay so the equation. Lets say e is explorers and v is flying vs and m = money.

e + v > or = 30.

80e + 5v =m.
 
e < or = 20\
v < or = 20.
Okay, the most money he could make would be if he made 20 explorers at 80 dollars and 10 vs at 5 dollars.
Total money...
1600 + 50 = 1650.
So he could make $1650.

7 0
3 years ago
The number of hours a lightbulb burns before failing varies from bulb to bulb. The population distribution of burnout times is s
liubo4ka [24]

ANSWER:

The average burnout time of a large number of bulbs has a sampling distribution that is close to Normal.

STEP-BY-STEP EXPLANATION:

The cental limit theorem states, that id the sample size is large (30 or more), then the sampling distribution of the sample means is approximately normal with mean ц and standar deviation б/\sqrt{n}

Thus the correct answer is the average burnout time of a large number of bulbs has a sampling distribution that is close to Normal.

6 0
3 years ago
Which of these items is a tax deduction?
Flura [38]
I'll just provide you some tax deductions.
1) sales tax. 
2) state tax
3) health insurance premiums *subject to limitations
4) tax savings for teachers *up to $250 for materials
5) charitable gifts
6) lifetime learning
7) unusual business expense
8) looking for job at the same field *cost incurred during job hunting can be deductible but still subject to limitation
9) self-employed social security

7 0
3 years ago
The probability that a student is accepted to a prestigious college is 0.3. If 5 students from the same school apply, what is th
hodyreva [135]

Answer:0.849185

Step-by-step explanation:

Binomial probability formula we will use:

$P(x)=\frac{n !}{x !(n-x) !} p^{x} q^{n-x}$

where,

n=5$\\$\mathrm{P}$ (probability of success) $=0.3$\\q=1-p

The computation of the probability will be :

$P(x \leq 2 ; 5,0.3)=P(x=0 ; 5,0.3)+P(x=1 ; 5,0.3)+P(x=2 ; 5,0.3)+P(x=3 ; 5,0.3)$\\$=\left[\frac{5 !}{5 !(5-0) !}(0.3)^{0}(1-0.3)^{5-0}\right]+\left[\frac{5 !}{5 !(5-1) !}(0.3)^{1}(1-0.3)^{5-1}\right]$$+\left[\frac{5 !}{5 !(5-2) !}(0.3)^{2}(1-0.3)^{5-2}\right]$$++\left[\frac{5 !}{5 !(5-3) !}(0.3)^{3}(1-0.3)^{5-3}\right]$$++\left[\frac{5 !}{5 !(5-4) !}(0.3)^{4}(1-0.3)^{5-4}\right]$\\$=0.1681+0.3601+0.3087+0.006615+0.00567$\\$\Rightarrow 0.849185$

The probability that at most 4 are accepted = 0.849185

6 0
3 years ago
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