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disa [49]
3 years ago
6

Can anyone help with this math problem?

Mathematics
2 answers:
Ne4ueva [31]3 years ago
6 0
The answer is 8. You rewrite the fraction as 5.25.
Galina-37 [17]3 years ago
5 0
The answer is 8 and 5.2
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Answer quick please I dont really get this
Triss [41]

Answer:

f(9) = 24

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 4(x - 3)

f(9) is x = 9

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em>:                    f(9) = 4(9 - 3)
  2. Subtract:                              f(9) = 4(6)
  3. Multiply:                               f(9) = 24
4 0
3 years ago
Find the average of the following numbers: * What is the average of the first n positive even numbers?
Allisa [31]

Answer:

Step-by-step explanation:

2+4+6+8+10/n = a

4 0
3 years ago
Cantidad de cajas cantudad de lapises​
ad-work [718]

Answer:

no lo sé

Step-by-step explanation:

Number of boxes number of pencils?

4 0
3 years ago
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Typographers measure font sizes in units called points. One point is equal to 1/72 inch. Esmeralda is typing a research paper on
IrinaK [193]
If 1 pt = 1/72 inch

and Esmeralda wants her text to be 1/72 inch tall

Surely, she should use 1 pt as her font size? 
8 0
3 years ago
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Consider the function f(x) = x^3 - 7x^2 - 2x + 14
mars1129 [50]

Answer:

There are 3 zeros, which are:

x=7,\:x=-\sqrt{2},\:x=\sqrt{2}

Step-by-step explanation:

Given the function

f\left(x\right)\:=\:x^3\:-\:7x^2\:-\:2x\:+\:14

To get the zeros of f(x), set y or f(x) =0

so

0=x^3-7x^2-2x+14

as

x^3\:-\:7x^2\:-\:2x\:+\:14=\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)

so

\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)=0

Using the zero factor principle:

\mathrm{ \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

so

x-7=0\quad \mathrm{or}\quad \:x+\sqrt{2}=0\quad \mathrm{or}\quad \:x-\sqrt{2}=0

solving

x-7=0

  • x=7

x+\sqrt{2}=0

  • x=-\sqrt{2}

x-\sqrt{2}=0

  • x=\sqrt{2}

Therefore, there are 3 zeros, which are:

x=7,\:x=-\sqrt{2},\:x=\sqrt{2}

8 0
3 years ago
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