Question

For what value(s) of k will the relation not be a function? A = {(3k−4, 16), (4k, 32)}

Answer 1

We won't have a function if for same value of x in (x,y) we get different values y.

So first step: figure out k so that the first coordinate (x) is the same:

3k-4=4k    | solve for k

k = -4

no check the values y for the elements of the relation

x = 3k-4 = -12-4=-16

so at -16 we get (-16,16) and (-16, 32), which mean for k=-4 the relation is not a function.

Let me know if you have any questions.

Answer 2

Answer:

K= -4

Step-by-step explanation:

Since it isn't possible that (3k-4, 16) is going to be equal to (4k, 32) in terms of positive numbers, you will have to go to the negative side of the number line.

K has to equal 4 because 3 · -4 = -12, and -12 minus 4 is equal to -16.

And since 4 · -4 = -16, K has to equal - 4.