Answer:
b.1
Explanation:
When we are using while loop to compute the product of several values we need to initialize the value holding the product to 1 because when we multiply something with 1 it will give the same number.
If we initialize it with 0 the product will come out to be 0 because anything multiplied by 0 is 0.
we cannot initialize it with NULL because it is not a pointer.
We need to initialize the number since it contains garbage values so it will give product with that value.
Answer:
Following are the program in java is given below
import java.util.*; // import package
public class Main // main class
{
public static void main(String[] args) // MAIN FUNCTION
{
Scanner scan2 = new Scanner(System.in);// scanner CLASS
System.out.println("Enter the Grade ");
char GRADE = scan2.next().charAt(0);//Read input by user
if(GRADE=='A' || GRADE=='B' || GRADE=='C' || GRADE=='D' || GRADE=='F' ) // //CHECK CONDITION
{
System.out.println("The GRADE is :" +GRADE); // display grade
}
else // Else block
{
System.out.println(" Input Error"); // display message
}
}
}
Output:
Enter the Grade
D
The GRADE is :D
Explanation:
Following are the description of program
- Create the object of scanner class for read the value of grade by the user .
- Read the value of "GRADE" variable by using the scanner class object scan 2
- Now check the condition in if block if the "GRADE" is 'A' or 'B' or 'C' or 'D' or 'F' then display the value of the GRADE variable otherwise else block is executed and input error message is displayed .
2
6
4
I’m guessing but this is my guess