It is (0,-1) hope that helps
Answer:
2 real roots
Step-by-step explanation:
If the discriminant is any positive number, that means the quadratic will have 2 real roots, or solutions.
Since the discriminant, 36, is a positive number, this will apply.
So, if the discriminant is 36, there will be 2 real roots.
Answer:
Given that:
=2^(-4/5)
This means that 2 is the base and -4/5 is the exponent.
To change it in radical form:
- firstly the denominator would be written with radical sign
- Then the negative sign with 4 will be removed by inverting the base.
- Then the fraction will be simplified according to the exponent (power)
- All the steps are performed below:
![=\sqrt[5]{2^{-4} } \\=\sqrt[5]{1/2^4}\\ =\sqrt[5]{1/16}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B5%5D%7B2%5E%7B-4%7D%20%7D%20%5C%5C%3D%5Csqrt%5B5%5D%7B1%2F2%5E4%7D%5C%5C%20%3D%5Csqrt%5B5%5D%7B1%2F16%7D)
i hope it will help you!
Answer:

Step-by-step explanation:
Consider linear differential equation 
It's solution is of form
where I.F is integrating factor given by
.
Given: 
We can write this equation as 
On comparing this equation with
, we get 
I.F =
{ formula used:
}
we get solution as follows:

{ formula used:
}
Applying condition:

So, we get solution as :
