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3 years ago

Help me and show your work

Mathematics

1 answer:

Sav [38]3 years ago

6 0

Kind of blurry, but hopefully it will help

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Distributive Property Using GCF<br><br> 25 + 30

postnew [5]

Hey there! I'm happy to help!

Let's look at the factors of each of these numbers.

1,25

5,5

1,30

2,15

3,10

5,6

The greatest common factor between these is 5. Therefore, we divide 25+30 by 5 and put the 5 on the outside.

5(5+6).

This has the same value but it is just written differently.

Have a wonderful day! :D

3 0

2 years ago

sergey [27]

Answer:80

Step-by-step explanation:

3 0

1 year ago

The geometric sequence graphed shows the number of mold spores in a Petri dish per day (please help!)

zavuch27 [327]

Answer:

f(1) = 2

f(n) = 2 × f(n - 1) , n ≥ 2

Step-by-step explanation:

the point of coordinates (1 , 2) is on the graph

Then

f(1) = 2

…………………………

We notice that :

f(2) = 4

f(3) = 8

f(4) = 16

16/8 = 8/4 = 4/2 = 2/1 = 2

________________________

This means the common ratio

of the geo sequence = 2

Hence ,

f(n) = 2 × f(n - 1)

5 0

1 year ago

The one-to-one functions g and h are defined as follows

Debora [2.8K]

Answer:

$g^-^1(x)=-8$

$h^-^1(x)=\frac{x-4}{3}$

$(h^-^1 \ o\ h)(-3)=-3$

Step-by-step explanation:

When given the following functions,

$g=[(-2,-7),(4,6),(6,-8),(7,4)]$

$h(x)=3x+4$

One is asked to find the following,

1. Question 1

$g^-^1(4)$

When finding the inverse of a function that is composed of defined points, one substitutes the input given into the function, then finds the output. After doing so, one must substitute the output into the function, and find its output. Thus, finding the inverse of the given input;

$g^-^1(4)$

$g(4)=6\\g(6)=-8\\g^-^1(4)=-8$

2. Question 2

$h^-^1(x)$

Finding the inverse of a continuous function is essentially finding the opposite of the function. An easy trick to do so is to treat the evaluator (h(x)) like another variable. Solve the equation for (x) in terms of (h(x)). Then rewrite the equation in inverse function notation,

$h(x)=3x+4\\\\h(x)-4=3x\\\\\frac{h(x)-4}{3}=x\\\\\frac{x-4}{3}=h^-^1(x)$

$h^-^1(x)=\frac{x-4}{3}$

3. Question 3

$(h^-^1 \ o\ h)(-3)$

This question essentially asks one to find the composition of the function. In essence, substitute function (h) into function ( $h^-^1$ ) and simplify. Then substitute (-3) into the result.