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DerKrebs [107]
4 years ago
12

Help me and show your work

Mathematics
1 answer:
Sav [38]4 years ago
6 0
Kind of blurry, but hopefully it will help

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Please help, I'll give Brainliest!!!
marin [14]
I blieve answer is A........mmmmmmmmmmmm
7 0
3 years ago
Can anyone please answer these for me?
yulyashka [42]

11.  y=-3x-5

12.  y=-5

13. y= -1/3x+5

14.  y=3x-5

3 0
3 years ago
HELPPPPP MEEEEEE Which one is not a solution to y = 3x - 5? A. (0, –5) B. (– 1, – 2) C. (5/3, 0) D. (2, 1)
nignag [31]

Answer:

Step-by-step explanation:

Let's examine the individual things

A. x=0 --> y=3.0-5=-5 True

B. x=-1 --> y=3.(-1)-5=-8 False

C. x=5/3 -->y=3(5/3)-5=0 True

D. x=2 --> y=3.2-5=1 True

Answer is B.

You don't understand, you can ask me :)

7 0
3 years ago
The side lengths of a 45-45-90 triangle are in the ratio 1 : 1: V2. What is tan 45°?
Artyom0805 [142]

Answer:

B. 1/2

Step-by-step explanation:

divide/

3 0
3 years ago
A teacher was interested in finding out whether a special study program would increase the scores of students on a national exam
bija089 [108]

Answer:

Check the explanation

Step-by-step explanation:

Going by the first attached image below we reject H_o against  H_1 if obs.T > t_{\alpha /2;n-1}

here obs.T=1.879

\therefore obs.T \ngtr 2.447=t_{0.025;6}

we accept H_o:\mu _{1}=\mu_{2} at 5% level of significance.

i.e there is no sufficient evidence to indicate that the special study program is more effective at 5% level of significance.

1.

this problem is simillar to the previous one except the alternative hypothesis.

Let X_i's denote the bonuses given by female managers and Y_i's denote the bonuses given by male managers.

we assume that X_i \sim N(\mu _{1},\sigma _{1}^{2}) Y_i \sim N(\mu _{2},\sigma _{2}^{2}) independently

We want to test H_0:\mu_{1}=\mu_{2} vs H_1:\mu_{1}\neq \mu_{2}

define D_i=X_i-Y_i , i=1(1)8

now D_i\sim N(\mu _{1}-\mu _{2}=\mu _{D},\sigma _{1}^{2}+\sigma _{2}^{2}=\sigma _{D}^{2}) , i=1(1)8

the hypothesis becomes

H_0:\mu_{D}=0 vs H_1:\mu_{D}\neq 0

in the third attached image, we use the same test statistic as before

i.e at 5% level of significance there is not enough evidence to indicate a difference in average bonuses .

3 0
3 years ago
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