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Ilia_Sergeevich [38]
3 years ago
10

Which expression is equivalent to 15x + 3?

Mathematics
2 answers:
kherson [118]3 years ago
6 0
It is 3(5x + 1). Multiply 3 with 5 and multiply 3 with 1, then you will get 15x + 3
Zigmanuir [339]3 years ago
5 0
The answer is 3(5x+1)
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Police response time to an emergency call is the difference between the time the call is first received by the dispatcher and th
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Answer:

a) 0.7683 = 76.83% probability that a randomly selected emergency call is between 5 and 10 minutes.

b) 0.0606 = 6.06% probability that a randomly received emergency call is of less than 5 min.

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Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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Mean of 8.1 minutes and a standard deviation of 2.0 minutes.

This means that \mu = 8.1, \sigma = 2

a. between 5 and 10 min

This is the p-value of Z when X = 10 subtracted by the p-value of Z when X = 5.

X = 10

Z = \frac{X - \mu}{\sigma}

Z = \frac{10 - 8.1}{2}

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X = 5

Z = \frac{X - \mu}{\sigma}

Z = \frac{5 - 8.1}{2}

Z = -1.55

Z = -1.55 has a p-value of  0.0606

0.8289 - 0.0606 = 0.7683

0.7683 = 76.83% probability that a randomly selected emergency call is between 5 and 10 minutes.

b. less than 5 min

p-value of Z when X = 5, which, found from item a, is of 0.0606

0.0606 = 6.06% probability that a randomly received emergency call is of less than 5 min.

c. more than 10 min

1 subtracted by the p-value of Z when X = 10, which, from item a, is of 0.8289

1 - 0.8289 = 0.1711

0.1711 = 17.11% probability that a randomly received emergency call is of more than 10 min.

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