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Ilia_Sergeevich [38]
3 years ago
10

Which expression is equivalent to 15x + 3?

Mathematics
2 answers:
kherson [118]3 years ago
6 0
It is 3(5x + 1). Multiply 3 with 5 and multiply 3 with 1, then you will get 15x + 3
Zigmanuir [339]3 years ago
5 0
The answer is 3(5x+1)
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Guys plssssssss! I want to spend time today and tomorrow with my fam before they go back to Washington
Nezavi [6.7K]

Answer:

10) It increased by appoxamately 17%.

11) 255 decreased by 20%

12) 15 increased by 66\frac{2}{3}%

13) $9,450

14) $149.8

15) $238.5

Step-by-step explanation:

10) 170 is greater than 150 by 25. 25 is 16\frac{2}{3}% of 150, so it increased by appoxamately 17%.

11) 225 is decreased by 45. 45 is 20% of 100, so 255 decreased by 20%

12) 15 is increased by 10. 10 is 66\frac{2}{3} of 15, so 15 increased by 66\frac{2}{3}%

13) 5% of 9,000 is 450. 450 + 9,000 is $9,450

14) 7% of 140 is is 9.8. 140 + 9.8 = $149.8

15) 6% of 225 is 13.5. 225 + 13.5 = $238.5

3 0
3 years ago
Show the work please
nadezda [96]
Its 16x^2 i'll give explanation in a second
8 0
3 years ago
Jin makes trail mix with apricots and walnuts. A package of dried apricots weighs 22.1 ounces. Jin divides the apricots equally
zysi [14]

Answer:

0.65  ounces

Step-by-step explanation:

divide 22.1 by 34

4 0
3 years ago
Read 2 more answers
Please help asap, I'm so confused lol.
Sladkaya [172]

Answer: $450

Step-by-step explanation:

We can form an equation representing the problem. The question is essentially asking 60% of what is equal to $270. If we define that what as a variable 'x', we get the following:

\frac{60}{100} *x=270

\frac{60x}{100} =270

Multiply both sides by 100:

\frac{60x}{100} *100=270*100

60x=27,000

Divide both sides by 60 to solve for the value of 'x':

x=\frac{27,000}{60} =450

Answer is 450 bucks

We can check this answer by taking 60% of $450. In principal, this should return the discount of $270.

\frac{60}{100} *450=270

Yup, it checks out

8 0
2 years ago
Read 2 more answers
If f(x) = x2 – 1 and g(x) = 2x – 3, what is the domain
Ainat [17]
Begin by finding the lowest point the quadratic equation can be, the vertex; 

x²-1= is just a translation down of the graph x²

vertex; (0, -1) and since the graph of x² would extend to infinity beyond that point, we can say {x| x≥0} for domain and {y| y≥-1}. 

For the linear equation, it is possible to have all x and y values, therefore range and domain belong to all real numbers. 

Hope I helped :) 
5 0
4 years ago
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