As an opportunity to respond to people who might disagree with your claim.
Step-by-step explanation:
Given points are (-2,5) and (3,-17)
to find midpoint, use this formula
( x1+x2/2 , y1+y2/2)
where points are a(x1,y1) and b(x2,y2)
coming to the question,
midpoint is :
[ (-2-3)/2 , (5-17)/2 ]
[ -5/2 , -12/2 ]
[ -2.5 , -6 ]
OPTION
IS CORRECT
Given:
The zeros of the polynomial are
.
Degree = 4
Leading coefficient = 1
To find:
The polynomial.
Solution:
If c is a zero of a polynomial, then (x-c) must be a factor of the polynomial.
Here, -2,4,-5, 5, are zeros of the required polynomial, so (x+2), (x-4), (x+5), (x-5) are factors of required polynomial.

![[\because a^2-b^2=(a-b)(a+b)]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D)

Using distributive property, we get


On combining like terms, we get


Here, the leading coefficient is 1. So, it is the required polynomial.
Therefore, the correct option is E.
I can’t even see da the dawn question LOL