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3 years ago

What is the equation of a line with an intercept of -3 and a slope of 5?

Mathematics

1 answer:

Setler79 [48]3 years ago

7 0

Answer:

y= 5x-3

Step-by-step explanation:

We have an intercept of -3 and a slope of 5

We can use the slope intercept form of the equation

y= mx+b where m is the slope and b is the y intercept

Substituting in the known values.

y= 5x-3

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Solve the simultaneous equation <br> 2x - 5y = 9<br> 3x + 4y = 2

lianna [129]

Answer:

x = 2, y = -1.

Step-by-step explanation:

2x - 5y = 9

3x + 4y = 2

Multiply first equation by -3 and the second by 2:

-6x + 15y = -27

6x + 8y = 4 Adding the 2 equations:

23y = -23

y = -1.

Now substitute this value for y in the first equation:

2x - 5(-1) = 9

2x = 9 +5(-1)

2x = 9 - 5

2x = 4

x = 2.

8 0

3 years ago

Select the action you would use to solve x-3= 12. Then select the property that justifies that action.

Akimi4 [234]

Answer:

Step-by-step explanation:

you would add three to both sides because you are subtracting on the left side, so you would use inverse operations

6 0

3 years ago

at the school fair, of the people are under 16 years old. one-third of the people are teachers. if there are at least 21 one tea

Diano4ka-milaya [45]

Hello there!

Your correct answer will be 35 people under 16.

You know that 1/3 of the people are teachers, which means that 2/3 of people are left. Now, you need to get to the decimal value (.667). Make that number 1.667, because there will not be less teachers than students. Now, multiply:

1.667 x 21 = 35

There you go!
Brady

5 0

3 years ago

Can you help me find the composition of funtions

balandron [24]

where's the question? x

6 0

3 years ago

7+3√5/3+√5 - 7-3√5/3-√5 = a + b√5

daser333 [38]

<h3>Given:-</h3>

$\\ \sf \implies\frac{7 + 3 \sqrt{5} }{3 + \sqrt{5} } - \frac{7 - 3 \sqrt{5} }{3 - \sqrt{5} } = a + \sqrt{5} b \\$

The value of a and b

<h3>Solution:-</h3>

$\\ \sf \implies\frac{7 + 3 \sqrt{5} }{3 + \sqrt{5} } - \frac{7 - 3 \sqrt{5} }{3 - \sqrt{5} } = a + \sqrt{5} b \\$

$\\ \sf \implies\frac{( \: 7 + 3 \sqrt{5} \: \: ( 3 - \sqrt{5}) \: \: - 7 - 3 \sqrt{5} \: \: ( 3 + \sqrt{5}) \: }{(3 + \sqrt{5}) \: \:(3 + \sqrt{5}) } = a + \sqrt{5} \: b\\$

$\\ \sf \implies\frac{( \: 21 - 7 \sqrt{5} \: + 9 \sqrt{5} - 15) \: \: - ( \: 21 + 7 \sqrt{5} \: - 9 \sqrt{5} + 15)\: }{(3 + \sqrt{5}) \: \:(3 + \sqrt{5}) } = a + \sqrt{5} \: b\\$

$\\ \sf \implies\frac{( \: 6 + 2 \sqrt{5} ) \: \: - ( \: 6 - 2 \sqrt{5} )\: }{(3 + \sqrt{5}) \: \:(3 + \sqrt{5}) } = a + \sqrt{5} \: b\\$

$\\ \sf \implies\frac{\: 6 + 2 \sqrt{5} \: \: - \: \: 6 - 2 \sqrt{5} \: }{(3 + \sqrt{5}) \: \:(3 + \sqrt{5}) } = a + \sqrt{5} \: b\\$

$\\ \sf \implies\frac{\: 4 \sqrt{5} \: \: }{3 {}^{2} - {\sqrt{5} }^{2} } = a + \sqrt{5} \: b\\$

$\\ \sf \implies\frac{\: 4 \sqrt{5} \: \: }{ \: \: \: \: 9 - 5 \: \: \: } = a + \sqrt{5} \: b\\$

$\\ \sf \implies\frac{\: 4 \sqrt{5} \: \: }{ \: \: \: \: 4 \: \: \: } = a + \sqrt{5} \: b\\$

$\\ \sf \implies\frac{\: \cancel{4 } \sqrt{5} \: \: }{ \: \: \: \: \cancel{4 }\: \: \: } = a + \sqrt{5} \: b\\$

$\\ \sf \implies \: \sqrt{5} = a + \sqrt{5} \: b\\$

we can also write it as ;

$\\ \sf \implies \: 0 + \sqrt{5} = a + \sqrt{5} \: b\\$

★<u> </u><u>Henceforth, the value of a and b are</u> :

→ a = 0

→ b = 1

6 0

2 years ago

Read 2 more answers