What is the equation of a line with an intercept of -3 and a slope of 5?

Mathematics

1 answer:

Setler79 [48]3 years ago

7 0

Answer:

y= 5x-3

Step-by-step explanation:

We have an intercept of -3 and a slope of 5

We can use the slope intercept form of the equation

y= mx+b where m is the slope and b is the y intercept

Substituting in the known values.

y= 5x-3

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Let alpha and beta be conjugate complex numbers such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}

miskamm [114]

Answer:

$-3+i\sqrt{3} , 1+\sqrt{3}$

Step-by-step explanation:

Given that alpha and beta be conjugate complex numbers

such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}.

Let

$\alpha = x+iy\\\beta = x-iy$

since they are conjugates

$\alpha-\beta = x+iy-(x-iy)\\= 2iy= 2i\sqrt{3} \\y =\sqrt{3}$

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