Answer:
The sample size needed is 2401.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error of the interval is:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
Estimate the sample size needed if no estimate of p is available so that the confidence interval will have a margin of error of 0.02.
We have to find n, for which M = 0.02.
There is no estimate of p available, so we use 
The sample size needed is 2401.
Given:
The probability for success of an event is P(A)
The probability of success of a second, independent event is P(B).
To find:
The probability of both events occurring, in that order.
Solution:
If A and B are two independent events, then
It is given that,
The probability for success of an event is P(A)
The probability of success of a second, independent event is P(B).
Since A and B both are independent event and we need to find the probability of both events occurring, in that order, i.e., 
, therefore .
Hence, the correct option is A.
400+30+7. +0+4
3,000,000+500+40+3,000+2+1
Answer: 132 miles is the answer
Step-by-step explanation: hope this help people:)
