All categories

3 years ago

Pls help me I’ll mark brainliest!!

Mathematics

2 answers:

dimulka [17.4K]3 years ago

5 0

Answer:

75 please mark me brainliest

Step-by-step explanation:

saveliy_v [14]3 years ago

5 0

Answer:

x=33

Step-by-step explanation:

Those are corresponding angles, so they are equal:

4x-14=x+85

Put all the x's on one side:

3x=85+14=99

Simplify:

x=33

You might be interested in

I also need help with these two

lorasvet [3.4K]

Answer: #13 you need to know that the sides are equal. #14 (7,6)

Step-by-step explanation: #14 in picture

4 0

3 years ago

Please help! (100 points!) look at the image :)

viva [34]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

If f(x)=2−x12 and g(x)=x2−9, what is the domain of g(x)÷f(x)?

Keith_Richards [23]

$\bf \begin{cases}
f(x)=2-x^{12}\\
g(x)=x^2-9\\
g(x)\div f(x)=\frac{g(x)}{f(x)}
\end{cases}\implies \cfrac{x^2-9}{2-x^{12}}$

now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to undefined.

now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.

$\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\
-------------------------------\\\\
\cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}$

so, the domain is all real numbers EXCEPT that one.

4 0

3 years ago

Perform the indicated operation. -8 + (-4)

Lostsunrise [7]

It is -12, negative + negative is Negative unless if its with a positive it will cancel out

ex, -12 + 6= -6

3 0

3 years ago

2. Given: g(x) = x2 What is g(4) = ? 4 0 16 49

Fed [463]

Answer:

Step-by-step explanation:

Simply plug 4 into g(x)

g(x) = x^2

g(4) = (4)^2 = 16

4 0

3 years ago