Find the equation of line passes through point (2, 5) and perpendicular to line having equation y =- 2/3x +3
<h3><u>Answer:</u></h3>
The equation of line passes through point (2, 5) and perpendicular to line having equation y =- 2/3x +3 in slope intercept form is ![y = \frac{3}{2}x + 2](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B3%7D%7B2%7Dx%20%2B%202)
<h3><u>Solution:</u></h3>
Given that line passes through (2, 5) and perpendicular to line having equation ![y = \frac{-2}{3}x + 3](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B-2%7D%7B3%7Dx%20%2B%203)
Let us first find slope of original line
<em><u>The slope intercept form of line is given as:</u></em>
y = mx + c ------ eqn 1
Where "m" is the slope of line and "c" is the y - intercept
On comparing the slope intercept form y = mx + c and given equation of line
we get
![m = \frac{-2}{3}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B-2%7D%7B3%7D)
Thus slope of given line is ![m = \frac{-2}{3}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B-2%7D%7B3%7D)
We know that product of slopes of given line and slope of line perpendicular to given line is always -1
Slope of given line x slope of line perpendicular to it = -1
![\begin{array}{l}{\frac{-2}{3} \times \text { slope of line perpendicular to it }=-1} \\\\ {\text { slope of line perpendicular to it }=\frac{3}{2}}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5Cfrac%7B-2%7D%7B3%7D%20%5Ctimes%20%5Ctext%20%7B%20slope%20of%20line%20perpendicular%20to%20it%20%7D%3D-1%7D%20%5C%5C%5C%5C%20%7B%5Ctext%20%7B%20slope%20of%20line%20perpendicular%20to%20it%20%7D%3D%5Cfrac%7B3%7D%7B2%7D%7D%5Cend%7Barray%7D)
Let us find equation of line with slope
and passes through (2, 5)
Substitute
and (x, y) = (2, 5)
![5 = \frac{3}{2} \times 2 + c\\\\5 = 3 + c\\\\c = 2](https://tex.z-dn.net/?f=5%20%3D%20%5Cfrac%7B3%7D%7B2%7D%20%5Ctimes%202%20%2B%20c%5C%5C%5C%5C5%20%3D%203%20%2B%20c%5C%5C%5C%5Cc%20%3D%202)
<em><u>Thus the required equation of line is:</u></em>
Substitute
and c = 2 in eqn 1
![y = \frac{3}{2}x + 2](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B3%7D%7B2%7Dx%20%2B%202)
Thus the equation of line perpendicular to given line is found out