Three consecutive even numbers have a sum between 84 and 96.
1 answer:
Answer:
a. 84 < n + (n + 2) + (n + 4) < 96
b. 26 < n < 30
Step-by-step explanation:
Let n = 1st number
n+2 2nd even number
n+4 = 3rd even number
The sum of these 3 numbers is
n+n+2+n+4
It must be between 84 and 96 (it does not include this 84 and 96)
84< n+n+2+n+4 < 96
Now we need to solve this
Combine like terms
84 < 3n +6< 96
Subtract 6 from all sides
84 -6 < 3n+6-6 < 96 -6
78 < 3n < 90
Divide all sides by 3
78/3 < 3n/3 < 90/3
26 < n< 30
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Answer:
It is a solution to the equation
Step-by-step explanation:
We just need to bring the value 9 to the right hand side of the equation
So we have;
x = 17 -9
x = 8
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<span>10.5 in Scientific Notation
= 1.05 x 10^-1
------------</span>
X=12
(10(12)-20) = 120-20 = 100
(6(12)+8) = 72+8=80
100+80 = 180