Three consecutive even numbers have a sum between 84 and 96.

Mathematics

1 answer:

ELEN [110]3 years ago

5 0

Answer:

a. 84 < n + (n + 2) + (n + 4) < 96

b. 26 < n < 30

Step-by-step explanation:

Let n = 1st number

n+2 2nd even number

n+4 = 3rd even number

The sum of these 3 numbers is

n+n+2+n+4

It must be between 84 and 96 (it does not include this 84 and 96)

84< n+n+2+n+4 < 96

Now we need to solve this

Combine like terms

84 < 3n +6< 96

Subtract 6 from all sides

84 -6 < 3n+6-6 < 96 -6

78 < 3n < 90

Divide all sides by 3

78/3 < 3n/3 < 90/3

26 < n< 30

You might be interested in

Jerome wrote the following scenario to match the algebraic expression s 4 − 16: “16 fewer than four times the number of songs on

Xelga [282]

Answer:

No, because the expression s/4 - 16. In the word formed she times 4 and the letter, she should have to dived it.

Step-by-step explanation:

No, because the expression s/4 - 16. In the word formed she times 4 and the letter, she should have to dived it.

5 0

3 years ago

Read 2 more answers

Sam opened a savings account with an initial deposit of $2,000. Since then, he has never made any other deposits or withdrawals.

notsponge [240]

If my math is correct B or C is what it comes down to

7 0

3 years ago

Read 2 more answers

Can someone please help me with this?

geniusboy [140]

Answer: B and D

Step-by-step explanation:

First, solve the terms inside of the parenthesis. As a general rule, whenever you multiply two terms that have the same base, you can add their exponents.

Applying this rule, the base in the problem is 6, and the exponents are 3 and -4. The sum of 3 and -4 leaves -1. Therefore, this is one of our solutions:

$(6^-^1)^-^3$

When you have an exponential term raised to another exponent, you can simply multiply the exponents. In the previous solution given above, multiply -1 and -3 to get 3. Therefore our second solution is:

$6^3$