Answer:
The company should take a sample of 148 boxes.
Step-by-step explanation:
Hello!
The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.
They estimated a "pilot" proportion of p'=0.20
And using a 90% confidence level the CI should have a margin of error of 2% (0.02).
The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"
[p' ±
]
Where
p' is the sample proportion/point estimator of the population proportion
is the margin of error (d) of the confidence interval.

So






n= 147.28 ≅ 148 boxes.
I hope it helps!
3d=12
This should be your equation
And if it is asking for the answer it would be 4
I hope this answer helps!
Answer:
No solution
Step-by-step explanation:
5(x + 4) – x = 4(x + 5) – 1
x = ?
Solution:
5(x+4)−x=4(x+5)−1
Apply Distributive property:
- (5)(x)+(5)(4)−x=(4)(x)+(4)(5)−1
- 5x+20−x=4x+20−1
Combine Like Terms:
- (5x−x)+(20)=(4x)+(20−1)
- 4x+20=4x+19
- 4x+20=4x+19
Subtract 4x from both sides:
Subtract 20 from both sides:
There isn't any solutions.
If 2 lb of bananas cost $1.16, then each pound costs $0.58.
0.58 * 5 = 2.9
So 5 lb of bananas will cost $2.90.
Hope this helps!
hear here is your answer in attachment attach