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vladimir2022 [97]
3 years ago
12

Tickets for an amusement park cost $10 for adults and 6 for children find the total cost of 2 adults and 3 children

Mathematics
2 answers:
almond37 [142]3 years ago
6 0
The answer is $38

you take 10+10 because there are two adults, then take 6+6+6 because there are 3 children.
wolverine [178]3 years ago
3 0

It would be $38 total, because it would be 20 for the adults and 18 for the children

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If using the method of completing the square to solve the quadratic equation
Assoli18 [71]

Answer:

The number would have to be added is 2

Step-by-step explanation:

To find the form of the completing square of the quadratic function:

  • Divide the coefficient of x by 2
  • Square the quotient
  • Subtract the numerical term from the square of the quotient

Let us do these steps with our question

∵ x² - 2x - 1 = 0

→ Divide the coefficient of x by 2

∵ The coefficient of x is -2

∴ -2 ÷ 2 = -1

→ Square the -1

∵ (-1)² = 1

→ Subtract the numerical term from 1

∵ The numerical term = -1

∵ 1 - (-1) = 1 + 1 = 2

∴ We must add 2 to -1 to get 1

→ (x² - 2x - 1 + 2) - 2 = 0

→ (x² - 2x + 1) = 2

→ (x - 1)² = 2

The number would have to be added is 2

4 0
3 years ago
3/4 times 7/6 in simplest form
Artyom0805 [142]
3/4 times 7/6 in simplest form = 0.875
7 0
3 years ago
Read 2 more answers
What is the area of this rhombus?
ioda

Answer:

90 m²

Step-by-step explanation:

A=\frac{pq}{2}

10 · 18

180

180 ÷ 2

90

3 0
3 years ago
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If logb2=x and logb3=y, evaluate the following in terms of x and y:
Alja [10]

log_b{162} = x + 4y\\\\log_b324 = 2x+4y\\\\log_b\frac{8}{9} = 3x-2y\\\\\frac{log_b27}{log_b16} = 3y-4x

<em><u>Solution:</u></em>

Given that,

log_b2 = x\\\\log_b3 = y --------(i)

<em><u>Use the following log rules</u></em>

Rule 1: log_b(ac) = log_ba + log_bc

Rule 2: log_b\frac{a}{c} = log_ba - log_bc

Rule 3: log_ba^c = clog_ba

a) log_b{162}

Break 162 down to primes:

162 = 2^1 \times 3^4

log_b{162} =log_b 2^1. 3^4\\\\By\ rule\ 1\\\\ log_b{162} = log_b 2^1 +log_b 3^4\\\\By\ rule\ 3\\\\1log_b2 + 4log_b3\\\\1x+4y\\\\x+4y

Thus we get,

log_b162 = x + 4y

Next

b) log_b 324

Break 324 down to primes:

324 = 2^2 \times 3^4

log_b324 = log_b 2^2.3^4\\\\By\ rule\ 1\\\\log_b324 = log_b2^2 + log_b3^4\\\\By\ rule\ 3\\\\log_b324 = 2log_b2 + 4log_b3\\\\From\ (i)\\\\log_b324 = 2x + 4y

Next

c) log_b\frac{8}{9}

By rule 2

log_b\frac{8}{9} = log_b8 - log_b9\\\\log_b\frac{8}{9} = log_b 2^3 - log_b3^2\\\\By\ rule\ 3\\\\log_b\frac{8}{9} =  3 log_b2 - 2log_b3\\\\From\ (i)\\\\log_b\frac{8}{9} =  3x - 2y

Next

d) \frac{log_b27}{log_b16}

By rule 2

\frac{log_b27}{log_b16} = log_b27 - log_b16\\\\ \frac{log_b27}{log_b16} = log_b3^3 - log_b2^4\\\\By\ rule\ 2\\\\ \frac{log_b27}{log_b16} = 3log_b3 - 4log_b2 \\\\From\ (i)\\\\\frac{log_b27}{log_b16} =  3y - 4x

Thus the given are evaluated in terms of x and y

3 0
3 years ago
PLEASE HELP!!! EVERYTHING IS IN THE PICTURE!
Alex_Xolod [135]

Answer:

the answer is D

Step-by-step explanation:

3 0
3 years ago
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