The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
</span>
Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Answer:
<h2>infinitely many solutions</h2>
Step-by-step explanation:
5x - 6 = 3x - 6 + 2x <em>combine like terms</em>
5x - 6 = (3x + 2x) - 6
5x - 6 = 5x - 6 <em>subtract 5x from both sides</em>
-6 = -6 TRUE
Therefore the equation has infinitely many solutions.
<h3>Answer:</h3>
Mean: 17.2
Median: 18
Mode: 18
<h3>Solution:</h3>
Mean: The sum of all observation divided by several observation
- 20+18+13+17+18=86
- 86÷5=
- 17.2
Median:it is the middlemost observation of data arraged in increasing or decreasing order of values
- (13,17,18,18,20)
- (17,18,18)
- (18)
Mode:it is the value that occurs frequently in a set of data
Hope it helps
Answer:
Answer
Let height =h
Total surface area=2πr(r+h)
r=7cm
⇒968=2×
7
22
×7(7+h)
⇒
44
968
=7+h
⇒h+7=22
⇒h=22−7
=15cm.
Step-by-step explanation:
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