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dybincka [34]
3 years ago
9

Sheila and Lenore were driving to their grandmother’s house. Lenore left 1 hour after Sheila. Sheila drove at a rate of 45mph, a

nd Lenore drove at a rate of 60mph. How long will it take for Lenore to catch up to Sheila?
Mathematics
1 answer:
solong [7]3 years ago
4 0

Answer:

It'll take 3 h before Lenore catch up to Sheila.

Step-by-step explanation:

To solve this problem we first need to calculate the relative speed between the two. Since they're going at the same direction we need to subtract their individual speeds if their directions were oposite we would have to sum their speeds. In this case we have:

relative speed = Lenore speed - Sheila speed

relative speed = 60 - 45 = 15 mph

Since Sheila left 1 h before Lenore and she drove at a rate of 45 mph, then she had covered a distance of:

distance = time*speed = 1*45 = 45 miles

Before Lenore left, so in order for Lenore to catch up to Sheila she needs to cover that distance at a relative speed of 15 mph.

time = distance/(relative speed) = 45/15 = 3 h

It'll take 3 h before Lenore catch up to Sheila.

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julsineya [31]
A) 19m because 3 times 6 is 18 then you add m, which would be 19m
5 0
2 years ago
What is the sum of each pair of binary integers?
Natali5045456 [20]
Add digit by digit, from the right, just like any number, except that if it adds to 2, then put a zero and carry one (instead of carrying when it adds to 10 or more).

Example:  < means carry, decimal equivalent for checking
1011+1111

     1     0     1     1         (8+2+1=11)
+   1     1     1     1         (8+4+2+1=15)
---<---<----<----<----
1   1     0     1     0         (16+8+2=26)

Proceeding similarly,
a. 10101111+11011011 = 110001010  (394)
b. 10010111+11111111  = 110010110  (406)
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3 0
3 years ago
Calculate the distance between A and B
zloy xaker [14]

Answer:

7 units

Step-by-step explanation:

Simply count the units between A and B :)

3 0
2 years ago
A scientist is studying wildlife in Ohio and she estimates that the population of bats is tripling every year. If she had counte
Sloan [31]

The number of bats that there would be in 2021 would be 768,000.

<h3>What would be the number of bats in 2021?</h3>

The formula that can be used to determine the future value of bats in 2021 is:

FV = P (1 + r)^n

Where:

  • FV = Future value
  • P = Present value = 3000
  • R = interest rate = 300%
  • N = number of years = 4

3000(1 + 3)^4

3000 x 4^4 = 768,000

To learn more about future value, please check: brainly.com/question/18760477

8 0
2 years ago
Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in
Law Incorporation [45]

Answer:

(a) 900

(b) [567.35 , 1689.72]

(c) [23.82 , 41.11]

Step-by-step explanation:

We are given that a sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms i.e.;

Sample mean, xbar = 290      Sample standard deviation, s = 30  and  Sample size, n = 20

(a) Point estimate of the population variance is equal to sample variance, which is the square of Sample standard deviation ;

                         \sigma^{2}  =  s^{2} = 30^{2}

                          \sigma^{2}  = 900

(b) 90% confidence interval estimate of the population variance is given by the pivotal quantity of  \frac{(n-1)s^{2} }{\sigma^{2} } ~ \chi^{2} __n_-_1

P(10.12 < \chi^{2}__1_9 < 30.14) = 0.90 {At 10% significance level chi square has critical

                                           values of 10.12 and 30.14 at 19 degree of freedom}        

P(10.12 < \frac{(n-1)s^{2} }{\sigma^{2} } < 30.14) = 0.90

P(\frac{10.12}{(n-1)s^{2} } < \frac{1 }{\sigma^{2} } < \frac{30.14}{(n-1)s^{2} } ) = 0.90

P(\frac{(n-1)s^{2} }{30.14} < \sigma^{2} < \frac{(n-1)s^{2} }{10.12} ) = 0.90

90% confidence interval for \sigma^{2} = [\frac{19s^{2} }{30.14} , \frac{19s^{2} }{10.12}]

                                                   = [\frac{19*900 }{30.14} , \frac{19*900 }{10.12}]

                                                   = [567.35 , 1689.72]

Therefore, 90% confidence interval estimate of the population variance is [567.35 , 1689.72] .

(c) 90% confidence interval estimate of the population standard deviation is given by ;

       P(\sqrt{\frac{(n-1)s^{2} }{30.14}} < \sigma < \sqrt{\frac{(n-1)s^{2} }{10.12}} ) = 0.90

90% confidence interval for \sigma = [\sqrt{\frac{19s^{2} }{30.14}}   , \sqrt{\frac{19s^{2} }{10.12}}  ]

                                                 = [23.82 , 41.11]

Therefore, 90% confidence interval estimate of the population standard deviation is [23.82 , 41.11] .

7 0
3 years ago
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