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BlackZzzverrR [31]
3 years ago
11

Grammy is buying a pair of Jeans that regularly cost $40. They are on sale for 20% off.

Mathematics
1 answer:
Olin [163]3 years ago
8 0

Answer:

$34.56

Step-by-step explanation:

First, find the discount price.

20% of 40

20/100 x 40= $8

Deduct the discount from the original price.

40 - 8 = $32

This is the discount price.

Now, find 8% (tax) of the price.

8/100 x 32 = $2.56

Add it to the price.

32 + 2.56 = $34.56

Hope this helps!

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yanalaym [24]
The equation of any circle is

(x - a)^2 + (y - b)^2 = radius^2 where our center is (a, b)

Therefore, our equation is as follows.

(x + 2)^2 + (y - 3)^2 = 16
5 0
3 years ago
Which formulas can be used to find the surface area of a right prism where p is the perimeter of the base, h is the height of th
svetoff [14.1K]

Answer:

SA=BA+LA and SA=BA+ph

Step-by-step explanation:

I just looked it up

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mafiozo [28]

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Step-by-step explanation:

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3 years ago
Scores on a standardized test are approximately normally distributed with a mean of 480 and a standard deviation of 90. A studen
77julia77 [94]

Answer: the student's score closest to 91 percentile.

Step-by-step explanation:

Since the scores on the standardized test are approximately normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = test scores.

µ = mean score

σ = standard deviation

From the information given,

µ = 480

σ = 90

If a student has a score of 600, then x = 600

For x = 600,

z = (600 - 480)/90 = 1.33

Looking at the normal distribution table, the probability corresponding to the z score is 0.91

the student's score closest to 91 percentile.

6 0
3 years ago
Vertices A(a, -6, 2), B(4,b,-9), C(3,5,c) and D(-2,-5,11) form a parallelogram. Determine the values of a,b,c.
Tomtit [17]

Let's do a quick draw to help us visualize the problem:

That's a generic parallelogram, to verify that it's a parallelogram we can see that

\begin{gathered} AB=CD \\  \\ BC=AD \end{gathered}

The opposite lengths are equal, then, let's do something similar here, let's say that

\vec{AB}=\vec{CD}

then

\begin{gathered} \vec{AB}=B-A=(4,b,-9)-(a,-6,2)=(4-a,b+6,-9-2) \\  \\ \vec{AB}=(4-a,b+6,-11) \end{gathered}

And the vector CD

\begin{gathered} \vec{CD}=D-C=(-2,-5,11)-(3,5,c)=(-2-3,-5-5,11-c) \\  \\ \vec{CD}=(-5,-10,11-c) \end{gathered}

Let's impose our condition

\begin{gathered} \begin{equation*} \vec{AB}=\vec{CD} \end{equation*} \\  \\ (4-a,b+6,-11)=(-5,-10,11-c) \\  \\  \end{gathered}

Then

\begin{gathered} 4-a=-5 \\  \\ b+6=-10 \\  \\ 11-c=-11 \end{gathered}

By solving that equations we get

\begin{gathered} a=9 \\  \\ b=-16 \\  \\ c=22 \end{gathered}

6 0
2 years ago
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