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Eduardwww [97]
3 years ago
12

1/4 (8x - 20) - 16 = 10x + 51

Mathematics
1 answer:
pochemuha3 years ago
7 0

Answer:

The answer is -9 (If your looking for x)

Step-by-step explanation: I would suggest using the app Photomap for this kind of stuff. You take a picture of an equation and it gives you a step by step explanation and the answer. Glad I could help!

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Wich number is thirty-six thousand, two hundred fourteen and nine thousandths? A 36,214.009 B 36,214.09 C 36,214.900 D 36,241.00
vovikov84 [41]
A is the correct Answer
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3 years ago
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17. The sum of interior angles in a polygon is related to its number of sides.
bonufazy [111]

s = 1800°

To find the sum of interior angles in a polygon you can use the following equation

(sides - 2) * 180\\\\(12 - 2) * 180\\(10) * 180\\1800\\

If this helped you a Brainliest would be appreciated!

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3 years ago
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HELP FOR BRAINLIEST !!
julia-pushkina [17]
D is the answer because rise over run is going to left and plus 2 is on the y axis
5 0
3 years ago
Solve dis attachment and show all work ( I got it all wrong and I want to know how to solve it )
DedPeter [7]
(a) First find the intersections of y=e^{2x-x^2} and y=2:

2=e^{2x-x^2}\implies \ln2=2x-x^2\implies x=1\pm\sqrt{1-\ln2}

So the area of R is given by

\displaystyle\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\left(e^{2x-x^2}-2\right)\,\mathrm dx

If you're not familiar with the error function \mathrm{erf}(x), then you will not be able to find an exact answer. Fortunately, I see this is a question on a calculator based exam, so you can use whatever built-in function you have on your calculator to evaluate the integral. You should get something around 0.5141.

(b) Find the intersections of the line y=1 with y=e^{2x-x^2}.

1=e^{2x-x^2}\implies 0=2x-x^2\implies x=0,x=2

So the area of S is given by

\displaystyle\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}(2-1)\,\mathrm dx+\int_{1+\sqrt{1-\ln2}}^2\left(e^{2x-x^2}-1\right)\,\mathrm dx
\displaystyle=2\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\mathrm dx

which is approximately 1.546.

(c) The easiest method for finding the volume of the solid of revolution is via the disk method. Each cross-section of the solid is a circle with radius perpendicular to the x-axis, determined by the vertical distance from the curve y=e^{2x-x^2} and the line y=1, or e^{2x-x^2}-1. The area of any such circle is \pi times the square of its radius. Since the curve intersects the axis of revolution at x=0 and x=2, the volume would be given by

\displaystyle\pi\int_0^2\left(e^{2x-x^2}-1\right)^2\,\mathrm dx
5 0
3 years ago
I REALLY NEED HELP PLEEEASS Evelyn has $524.96 in her checking account. She must maintain a $500 balance to avoid a fee. She wro
m_a_m_a [10]
The answer is the first one. 524.96 - 32.50 + x ≥ 500; x ≥ $7.54
3 0
3 years ago
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