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Archy [21]
3 years ago
13

How to tell if a function has a vertical asymptote

Mathematics
1 answer:
diamong [38]3 years ago
4 0

Answer:

For a rational function, set the denominator equal to zero. Whatever value of x that makes the denominator equal to zero corresponds to the vertical asymptote.

Step-by-step explanation:

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prisoha [69]
Is there more to this? I don’t quite understand
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3 years ago
Ƒ(x) = x2 + 3x - 10. Determine the zeros of the equation.
7nadin3 [17]
I am assuming the equation is as follows
f(x) = x^2 + 3x - 10

Since the constant 10 is -10 this tells us we are going to have different signs + - after you have factored the equation.

First thing first. Think of two numbers that will give you the product(The answer after two numbers are multiplied) of -10 and the sum(Two numbers added together) of +3. I get the 3 from the 3x.

We know 5 x -2 = -10 and the sum 5 + -2 =  +3
With that said, we found our two factors
(x + 5)(x - 2)

Now write them as zeros and solve for x
x + 5 = 0
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So the zeros are -5 and 2.


3 0
4 years ago
The first three steps for solving the quadratic equation by completing the square are shown. Fill in the missing number in the l
gulaghasi [49]
Completing the square is done as follows:

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<span>9x2 +54x = 7
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<span>9(x2 + 6x) = 7
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5 0
3 years ago
Read 2 more answers
A number divided by three two is at most two
mart [117]

Answer:

X ≤ 2

Step-by-step explanation:

x/(3 - 2) ≤ 2

3-2 = 1

x/1 ≤ 2

X ≤ 2

3 0
3 years ago
May I know why is the answer 1/2? Any idea <br><br> Thank you!
ElenaW [278]

let's put value of t in equation.

x = 2√t

x = 2√y

x/2 = √y

(x/2)^2 = y

y = x^2 /4

now let's differentiate it with respect to x.

dy/dx = 2x/4 = x/2

differentiating again wrt to x

d^2y/dx^2 = 1/2

8 0
3 years ago
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