256 is the perfect square of 16 it would be 66 square root a2b
The vertex is at (2, 5).
To find the vertex, we first find the axis of symmetry; this is given by
x = -b/2a
For our equation, b = -16 and a = 4:
x = -(-16)/2(4) = 16/8 = 2
We substitute this back into our equation:
y = 4(2)² - 16(2) + 21 = 4(4) - 32 + 21 = 5
Therefore the vertex is at (2, 5).
Multiply and express as a mixed fraction
6 × 2 1/9
Answer: hold on
Step-by-step explanation: