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2 years ago

Compare the table and equation.

2 answers:

defon2 years ago

6 0

ANSWER

The table has the greater slope?

EXPLANATION

From the given table we can use any two ordered pairs to find the slope.

From the table, when

$x_1=2,y_1=10$

when

$x_2=3,y_2=15$

The slope formula is given by,

$m = \frac{y_1-y_2}{x_1-x_2}$
We substitute the values to obtain,

$m = \frac{10 - 15}{2 - 3}$
We simplify to get,

$m = \frac{-5}{ - 1} = 5$
As for the given equation

$y=4.5x$

the slope is
$m= 4.5$

Comparing the two slopes, we can see that,

$5\:>\:4.5$

Therefore the table has the greater slope.

prohojiy [21]2 years ago

4 0

Looking at the table you can see the Y goes up by 5 for each y. In the equation, the slope is only 4.5. The table has the greater slope.

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Cloud [144]

Answer:

8 family members. Average of 2.6 fish per person.

Step-by-step explanation:

How many family members caught fish? Count only those members who caught at least 1 fish (that's all of them, because nobody caught 0 fish!).

3 + 1 + 0 + 4 = 8 family members.

Average number of fish caught <u>per person</u>. This is the total number of fish caught divided by the total number of people.

This is a little bit tricky because, for example, 4 people caught 4 fish, making 4 x 4 = 16 fish caught.

Multiply number of fish (column 1) by the number of people (column 2):

1 x 3 + 2 x 1 + 3 x 0 + 4 x 4 = 3 + 2 + 0 + 16 = 21 fish caught.

21 fish. 8 people. On average, that is 21 / 8 = 2.625 which rounds to 2.6 fish per person.

Hint: the word "per" means <u>divide</u>, so "fish per person" tells you to divide the total number of fish by the total number of people.

Good Luck!

5 0

2 years ago

The numbers of teams remaining in each round of a single-elimination tennis tournament represent a geometric sequence where an i

Anit [1.1K]

Answer:

$a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}$

Step-by-step explanation:

We are given the following in the question:

The numbers of teams remaining in each round follows a geometric sequence.

Let a be the first the of the geometric sequence and r be the common ration.

The $n^{th}$ term of geometric sequence is given by:

$a_n = ar^{n-1}$

$a_4 = 16 = ar^3\\a_6 = 4 = ar^5$

Dividing the two equations, we get,

$\dfrac{16}{4} = \dfrac{ar^3}{ar^5}\\\\4}=\dfrac{1}{r^2}\\\\\Rightarrow r^2 = \dfrac{1}{4}\\\Rightarrow r = \dfrac{1}{2}$

the first term can be calculated as:

$16=a(\dfrac{1}{2})^3\\\\a = 16\times 6\\a = 128$

Thus, the required geometric sequence is

$a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}$

4 0

3 years ago

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Maurinko [17]

I think i only get some of it. this is what i did

x = -3 to 4y = 0.3 to 3if we use -3 and 3a < -1 < b
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3 years ago

Mrs. Tomas says that the number of students in her class on this week has no variability. Her student, Pierce, says that it does

user100 [1]

Answer:

Step-by-step explanation:

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2 years ago

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RSB [31]

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