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IRINA_888 [86]
3 years ago
8

Can please help!

Mathematics
1 answer:
sukhopar [10]3 years ago
5 0
Answer:
equation is: width = area / length
width = 62.5 yd

Explanation:
For the first rectangle:
We have:
length = 75 yd and width = 60 yd
Therefore:
area = length * width 
area = 75 * 60
area = 4500 yd²

For the second rectangle:
We have:
area = area of first rectangle = 4500 yd²
length = 72 yd
area = length * width
width = area / length ............> The required equation
width = 4500 / 72
width = 62.5 yd

Hope this helps :)
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a straight line has a equation 4x + 3y = 12 . find the gradient of the line and the coordinates of the point where this line cro
Komok [63]
4x + 3y = 12
3y = -4x + 12
y = -4/3x + 4........so the slope (or gradient) is -4/3...because in y = mx + b form, the slope(gradient) is in the m position and the y int is in the b position....so if u wanted to know the y axis, it would be (0,4)

the x intercept (where the line crosses the x axis) can be found by subbing in 0 for y in the original equation or the slope intercept equation, and solving for x.
4x + 3(0) = 12
4x = 12
x = 12/4 = 3....so the x intercept is (3,0)
4 0
3 years ago
Consider the population regression of log earnings [Yᵢ, where Yᵢ= ln(Earningsᵢ)] against two binary variables:
puteri [66]

Answer:

A) allows the population effect on log earnings of being married to depend on gender

Step-by-step explanation:

The regression equation of a dependent variable based on two or more independent variables is of the form:

Y=b_{0}+b_{1}X_{1} +b_{2}X_{2}+b_{3}X_{1}X_{2}

Here,

<em>Y</em> = dependent variable

X_{1} and X_{2} = independent variables

X_{1}X_{2} = interaction term

b_{1},\ b_{2}\ and \ b_{3} = regression coefficients.

If there is a significant interaction effect present then this implies that the effect of one independent variable (X_{1} orX_{2} ) on the dependent variable (<em>Y</em>) differs every time with different value of the other independent variable  (X_{1} orX_{2} ) .

The provided regression equation is:

Y_{i}=\beta _{0}+\beta _{1}D_{1i}+\beta_{2}D_{2i}+\beta _{3}D_{1i}D_{2i}+u_{i}

Y_{i} = dependent variable

D_{1i} and D_{2i} = independent variables

In this case the interaction term is defined as follows:

The effect of being married on log earnings is dependent on different values of the variables D_{2i}, i.e. the gender of the i^{th}person.

Thus, the correct option is (A).

3 0
3 years ago
What is 1/10 of 0.08
ZanzabumX [31]
1 / 10 of 0.08
1 / 10 * 0.08
0.08 / 10
0.008 Ans
4 0
3 years ago
Type the correct answer in each box. If necessary, use /for the fraction bars
Vikentia [17]

Answer:

The experimental probability of rolling an odd number is 60%, which is 10% more than the theoretical probability.

Step-by-step explanation:

The complete question is:

Type the correct answer in each box. Use numerals instead of words. If necessary, use/ for the fraction bar(s).

A special 8-sided die is marked with the numbers 1 to 8. It is rolled 20 times with these outcomes.

3, 4, 5, 2, 7, 1, 3, 7, 2, 6, 2, 1, 7, 3, 6, 1, 8, 3, 5, 6

The experimental probability of rolling an odd number is _%, which is _% more than the theoretical probability.

Solution:

The possible outcomes of rolling an 8-sided die are:

S = {1, 2, 3, 4, 5, 6, 7, 8}

The odd numbers are:

Odd = {1, 3, 5, 7} = 4 outcomes

The theoretical probability of rolling an odd number is:

P_{T}(\text{Odd})=\farc{4}{8}=\frac{1}{2}=50\%

Now from the given 20 outcomes the odd values are:

Odd = {3, 5, 7, 1, 3, 7, 1, 7, 3, 1, 3, 5} = 12 outcomes

Compute the experimental probability of rolling an odd number as follows:

P_{E}(\text{Odd})=\frac{12}{20}=\frac{3}{5}=60\%

Thus, the experimental probability of rolling an odd number is 60%, which is 10% more than the theoretical probability.

6 0
3 years ago
Pleas help me find the composition of goh and it’s domain
Ksivusya [100]

Solution:

The function is given below as

\begin{gathered} g(x)=\frac{x+4}{x-1} \\ h(x)=2x-1 \end{gathered}

To figure out

(goh)(x)

To do this , we will substitute x= 2x-1 in g(x)

\begin{gathered} g(x)=\frac{x+4}{x-1} \\ g(h)(x)=\frac{2x-1+4}{2x-1-1} \\ g(h)(x)=\frac{2x+3}{2x-2} \end{gathered}

Hence,

The composte function will be

(goh)(x)=\frac{2x+3}{2x-2}

Step 2:

To figure out the domain,

In mathematics, the domain of a function is the set of inputs accepted by the function.

Hence,

The domain of the function is

\begin{bmatrix}\mathrm{Solution:}\:&\:x1\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:1\right)\cup \left(1,\:\infty \:\right)\end{bmatrix}

5 0
1 year ago
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