Answer:
The answer to your question is only the second and the third are factors.
Step-by-step explanation:
Find the factors of 24x⁶ − 1029y³
First find the prime factors of 24 and 1029
24 2 1029 3
12 2 343 7 Then 24 = 2³3
6 2 49 7 1029 = 7³ 3
3 3 7 7
1 1
x⁶ = (x²)³ y³ = y³
Then
2³3(x²)³ - 7³ 3 y³
Factor 3 3[ 2³(x²)³ - 7³ y³]
Factor 3 [ (2x² - 7y)(4x⁴ + 14x²y + 49y²)]
Then
24
2x2 + 7y
4x4 + 14x2y + 49y2
All of the above
:
No.
Half of 48 would be 24, not 21
<3
A quadrilateral 24 ft long and 0 ft wide will have the smallest area.
<u>Finding x:</u>
We know that the diagonals of a rhombus bisect its angles
So, since US is a diagonal of the given rhombus:
∠RUS = ∠TUS
10x - 23 = 3x + 19 [replacing the given values of the angles]
7x - 23 = 19 [subtracting 3x from both sides]
7x = 42 [adding 23 on both sides]
x = 6 [dividing both sides by 7]
<u>Finding ∠RUT:</u>
We can see that:
∠RUT = ∠RUS + ∠TUS
<em>Since we are given the values of ∠RUS and ∠TUS:</em>
∠RUT = (10x - 23) + (3x + 19)
∠RUT = 13x - 4
<em>We know that x = 6:</em>
∠RUT = 13(6)- 4
∠RUT = 74°
−5−4.25⋅−7.4
Writing this to meet 20 character requirement