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ira [324]
2 years ago
14

If A and B are independent events with P( A) = 0.60 and P( B) = 0.70, then P( A or B) equals: a. 1.00 b. 0.42 c. 0.88 d. 1.30

Mathematics
1 answer:
Kruka [31]2 years ago
5 0

Answer:

The correct option is D

P(A or B) = 1.30

Step-by-step explanation:

Given two independent (or mutually exclusive) events with P(A) = 0.60, and P(B) = 0.70

P(A or B) = P(A) + P(B)

= 0.60 + 0.70

= 1.30

This is however absurd, as the probability of an event can only be less than or equal to 1, and not less than 0.

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What are the 10th and 90th percentiles of the distribution of sample proportion for the population proportion below?
levacccp [35]

Answer:

The 10th percentile is 0.0784.

The 90th percentile is 0.1616.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

For a proportion p in a sample of size n, we have that \mu = p, \sigma = \sqrt{\frac{p(1-p)}{n}}

In this problem, we have that:

\mu = 0.12, \sigma = \sqrt{\frac{0.12*0.88}{100}} = 0.0325

10th percentile:

X when Z has a pvalue of 0.1. So X when Z = -1.28.

Z = \frac{X - \mu}{\sigma}

-1.28 = \frac{X - 0.12}{0.0325}

X - 0.12 = -1.28*0.0325

X = 0.0784

The 10th percentile is 0.0784.

90th percentile:

X when Z has a pvalue of 0.9. So X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 0.12}{0.0325}

X - 0.12 = 1.28*0.0325

X = 0.1616

The 90th percentile is 0.1616.

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