Material=wall+2*side and material is 40 ft so:
40=w+2s
w=40-2s
Area=ws, using w from above we get:
A=(40-2s)s
A=40s-2s^2
dA/ds=40-4s and d2A/ds2=-4
Since d2A/ds2 is a constant negative acceleration, when dA/ds=0, A(s) is at an absolute maximum.
dA/ds=0 when 4s=40, s=10 ft
And since w=40-2s, w=20 ft
So the dimensions of the pen are 20 ft by 10 ft, with the 20 ft side being opposite the wall. And the maximum possible area is thus 200 ft^2
I think it would me 568 m
Answer:
Step-by-step explanation:
Answer:
4
Step-by-step explanation:
(segment piece) x (segment piece) = (segment piece) x (segment piece)
JN* NK = LN * NM
3x = 2*6
3x = 12
Divide by 3
3x/3 =12/3
x =4
