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Flura [38]
3 years ago
8

What is a set ? Give an example of a set .​

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
8 0

Answer: 24

Step-by-step explanation:

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Is the given point interior, exterior, or on the circle (x + 2)2 + (y - 3)2 = 81? R(6, 3)
ElenaW [278]
Hello : 
<span>(x + 2)² + (y-3)² = 9²
the center is : R(3 , 0 ) and radius   r = 9 
the </span> point D  is on the interior  if : RD <span>< 9
</span>the  point D  is on the exterior if :  RD > 9
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4 0
4 years ago
Read 2 more answers
[Calculus] particle at rest question. Show steps, please!
Vinvika [58]

Answer:

E

Step-by-step explanation:

We are given that a particle's position along the x-axis at time <em>t </em>is modeled by:

x(t)=2t^3-21t^2+72t-53

And we want to determine at which time(s) <em>t</em> is the particle at rest.

If the particle is at rest, this suggests that its velocity at that time is 0.

Since are we given the position function, we can differentiate it to find the velocity function.

So, by differentiating both sides with respect to <em>t</em>, we acquire:

\displaystyle x^\prime(t)=v(t)=\frac{d}{dt}\big[2t^3-21t^2+72t-53\big]

Differentiate. So, our velocity function is:

v(t)=6t^2-42t+72

So, we will set the velocity to 0 and solve for <em>t</em>. Hence:

0=6t^2-42t+72

We can divide both sides by 6:

0=t^2-7t+12

Factoring yields:

(t-3)(t-4)=0

By the Zero Product Property:

t-3\text{ and } t-4=0

Hence:

t=3\text{ and } t=4

Therefore, at the 3rd and 4th seconds, the velocity of the particle is 0, impling that the particle is at rest.

Our answer is E.

6 0
3 years ago
I need help please it's due today
Kazeer [188]

Answer:

11. False. 16≠ 64

12. True

13. True

14. False. 16≠8

15. 4(x-5) ,

6x+3

5 0
3 years ago
I need someone to teach me how to do at least half of these problems please help
Gwar [14]
Here, You need to substitute the value of x, and y, in the equation then check if L.H.S is equal to R.H.S or not. If they are equal then, ordered pair was correct, otherwise they are not applicable.

75) Here, oly option D can fit i the equation, we can check:
 3(-5) -2(-1) = -15+2 = -13 = R.H.S
So, the pairs are valid.

76) Here, only option D is your answer, 
4(2) - 4 = 8 - 4 = R.H.S

Do the same thing in every equation!

Hope this helps!
8 0
3 years ago
The following is a denegerate circle
horrorfan [7]
 x+y=2 x^2+y^2=-1 x^2+y<span>^2=1 (x-4)^2+(y-2)^2=0 </span>
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