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2 years ago

Is this correct? Or wrong

Mathematics

2 answers:

hjlf2 years ago

8 0

I believe you are right I checked the work and everything seems to be good !

Lostsunrise [7]2 years ago

3 0

Yes all looks good I checked it on my own.

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Find the volume of a sphere with a diameter of 8cm

12345 [234]

Answer:

V = 267.95

Step-by-step explanation:

Volume of a Sphere:

V = 4/3πr³

r = d/2

r = 4

Work:

V = 4/3πr³

V = 4/3(3.14)(4³)

V = 4/3(3.14)(64)

V = 267.95

3 0

2 years ago

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Need an explanation and answer for -25/28 ÷ (5/4)

lyudmila [28]

Answer:

-5/7

Step-by-step explanation:

When you divide fractions, you flip the second fraction, then multiply.

So it becomes -25/28 x 4/5.

This equals -100/140 which reduces to -5/7.

5 0

3 years ago

Mike owns two hardware stores. The scatter plots show the number of items sold at a specific price for each store for one week.

alexandr1967 [171]

The store that has more sales revenue is store A

6 0

2 years ago

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Which statement is true for brainliest

alexgriva [62]

Answer:

<A≅<Z

Step-by-step explanation:

Hope This Helps!

6 0

2 years ago

In the game of blackjack played with one deck, a player is initially dealt 2 different cards from the 52 different cards in the

Volgvan

Answer:

$P =4.83\%$

Step-by-step explanation:

First we calculate the number of possible ways to select 2 cards an ace and a card of 10 points.

There are 4 ace in the deck

There are 16 cards of 10 points in the deck

To make this calculation we use the formula of combinations

$nCr=\frac{n!}{r!(n-r)!}$

Where n is the total number of letters and r are chosen from them

The number of ways to choose 1 As is:

$4C1 = 4$

The number of ways to choose a 10-point letter is:

$16C1 = 16$

Therefore, the number of ways to choose an Ace and a 10-point card is:

$4C1 * 16C1 = 4 * 16 = 64$

Now the number of ways to choose any 2 cards from a deck of 52 cards is:

$52C2 =\frac{52!}{2!(52-2)!}$

$52C2 = 1326$

Therefore, the probability of obtaining an "blackjack" is:

$P = \frac{4C1 * 16C1}{52C2}$

$P = \frac{64}{1326}$

$P = \frac{32}{663}$

$P =0.0483$

$P =4.83\%$

4 0

2 years ago

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