There are 2 steaight lines , representing height an base of two buildings
Floor N > Floor S
Ground S > Ground N
Height = Ground x Floor
Then there must be some point that
Height N = Height S
this point is aprox at 2 floors
then Dayton was right
Solve for x. Enter the solutions from least to greatest. 4x^2 + 40x + 84 = 0
2 answers:
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Answer:
y=1/2x+2
Step-by-step explanation:
The equations come in the form of y=mx+c, where m is the gradient and c is the y-intercept. Looking at the graph we know that the y-intercept is (0,2), so that rules out options B and C.
To find the gradient is a little more tricky, but we can follow the formula:
, where rise is the vertical value and run is the horizontal value
So we sub in our values:
And simplify:
So now we sub in our new found values into y=mx+c:
y=1/2x+2