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Annette [7]
3 years ago
10

Is 13/10 irrational or rational

Mathematics
2 answers:
Akimi4 [234]3 years ago
5 0

Answer:

Yes

Step-by-step explanation:

Both 13 and 10 are integers, meaning 13.10 is rational.

motikmotik3 years ago
4 0
It is rational 13/10
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which expression have a value of 16/81? check all that apply. (2/3)^4, (16/3)^4, (4/81)^2, and (4/9)^2
notka56 [123]

Use\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\left(\dfrac{2}{3}\right)^4=\dfrac{2^4}{3^4}=\dfrac{16}{81}\ :)\\\\\left(\dfrac{16}{3}\right)^4=\dfrac{16^4}{3^4}=\dfrac{16^4}{81}\neq\dfrac{16}{81}\ :(\\\\\left(\dfrac{4}{81}\right)^2=\dfrac{4^2}{81^2}=\dfrac{16}{81^2}\neq\dfrac{16}{81}\ :(\\\\\left(\dfrac{4}{9}\right)^2=\dfrac{4^2}{9^2}=\dfrac{16}{81}\ :)

6 0
3 years ago
Read 2 more answers
What is 282% as a fraction in simplest form
RSB [31]
282% = 2.82 = 282/100 reduces to 141/50
8 0
2 years ago
Read 2 more answers
Which ordered pair makes both inequalities true?
Shalnov [3]

Answer:

The ordered pair which makes both the inequalities true is = (–2, 2)

Step-by-step explanation:

inequalities are the relationships between two expressions which are not equal to one another.

Inequalities are represented by the following relations:

  • ≤: "less than or equal to"
  • <: "less than"
  • ≠: "not equal to"
  • >: "greater than"
  • ≥: "greater than or equal to"

an inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions. It is used most often to compare two numbers on the number line by their size.

so, the option B(-2,2) satisfies  the inequalities expressions given in the question

therefore we can conclude that (-2,2) is the ordered pair which ,makes both the given inequalities true.

so the correct answer is (-2,2)

learn more about inequalities at

brainly.com/question/24853349

#SPJ10

7 0
2 years ago
Evaluate 10m + n2/4 when m = 5 and n = 4
Allushta [10]

Answer:

54

Step-by-step explanation:

we have

10m+\frac{n^{2}}{4}

For m=5.n=4

substitute the values of m and the value of n in the equation

so

10(5)+\frac{4^{2}}{4}

50+4

54

3 0
3 years ago
Choose the solutions of the following systems of equations x^2+y^2=6 and x^2-y=6
den301095 [7]

Answer:

The solutions are (-√6,0) and (√6,0)

(-√5,-1) and (√5,-1)

Step-by-step explanation:

The equations are:

{x}^{2}  +  {y}^{2}  = 6

and

{x}^{2}  - y = 6

We make y the subject in the second equation to get;

y =  {x}^{2}  - 6

We substitute into the first equation to get:

{x}^{2}  +  ({x}^{2}  - 6 )^2= 6

x =  \pm \sqrt{6}

and x =  \pm \sqrt{5}

The solutions are (-√6,0) and (√6,0)

(-√5,-1) and (√5,-1)

7 0
2 years ago
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