Write an explicit rule to represent the sequence: 20, 24, 28, 32, 36....
2 answers:
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Suppose for the moment that the inequality holds for all :
Expanding everything gives
In particular, the inequality says that for any choice of
. But if
and
, then
while
.
So one possible choice of could be
and
. Then we get
but clearly it's not true that .
The discontinuity are the point wherein the function is not defined.
The zeros are the points wherein f(x)=0.
Computing the discontinuity points:
Set
then the discontinuity point is at 
.
Comptine the zeroes:
Set
Compute the discriminant:
Then with quadratic formula we get the solutions:
The two zeros are
The zeros are the points wherein f(x)=0.
Computing the discontinuity points:
Set
Comptine the zeroes:
Set
Compute the discriminant:
Then with quadratic formula we get the solutions:
The two zeros are