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Tasya [4]
3 years ago
12

Shane wants to plant 28 marigold plants and 36 rose plants in his garden. What is the greatest number of rows possible if each r

ow has the same number of marigold plants and the same number of rose plants.
Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
6 0

Answer:

HCF=2*2=4

Step-by-step explanation:

Given :   Shane wants to plant 28 marigold plants and 36 rose plants in his garden  

To Find :  the greatest number of rows possible  each row has the same

number of marigold plants and the same number of rose plants.​

Solution:

marigold plants  = 28

rose plants = 36

To find  the greatest number of rows possible  if each row has the same

number of marigold plants and the same number of rose plants.​

we need to find HCF of 28 and 36

28 = 2 x 2 x 7

36 = 2 x 2 x 3 x 3

HCF = 2 x 2  = 4

greatest number of rows possible  is 4

Learn More:

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If the HCF of (p²-p-6) and (p²+3p-18) is (p-a). Find the value of a ...

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Step-by-step explanation:

Given definite integral is:

\int\limits^7_4 {\frac{x}{2}+x^{3}} \, dx \\f(x)=\frac{x}{2}+x^{3}---(1)\\\Delta x=\frac{b-a}{n}\\\\\Delta x=\frac{7-4}{n}=\frac{3}{n}\\\\x_{i}=a+\Delta xi\\a= Lower Limit=4\\\implies x_{i}=4+\frac{3}{n}i---(2)\\\\then\\f(x_{i})=\frac{x_{i}}{2}+x_{i}^{3}

Substituting (2) in above

f(x_{i})=\frac{1}{2}(4+\frac{3}{n}i)+(4+\frac{3}{n}i)^{3}\\\\f(x_{i})=(2+\frac{3}{2n}i)+(64+\frac{27}{n^{3}}i^{3}+3(16)\frac{3}{n}i+3(4)\frac{9}{n^{2}}i^{2})\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{3}{2n}i+\frac{144}{n}i+66\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{291}{2n}i+66\\\\f(x_{i})=3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

Riemann sum is:

= \lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

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Step-by-step explanation:

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Hello!

Unit rates can be written as ratios. In this case, we have 4 bushels in one hour, or 4:1. In eight hours, we can multiply like a fraction, multiplying both by eight to get eight hours.

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Answer:

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Step-by-step explanation:

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