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Neko [114]
2 years ago
13

Lena has started painting her room. She is down to her last can of paint. The cans of paint that she is using are 11 inches tall

and have a diameter of 7 inches. How much paint does she have left if the paint is now 2 inches from the top of the can?
Question options:

134.75π in3

110.25π in3

154π in3

22π in3
Mathematics
1 answer:
MrRissso [65]2 years ago
3 0

Answer:

110.25π in^{3}

Step-by-step explanation:

The can is a circular cylinder and has the formula for the volume to be

V = \pi r^{2} h

r = 3.5 and h = 11

Since the paint is now 2 in. from the top of the can, then there are 9 in. left in the can, which means there is 9/11 of the total volume in the can.

Therefore,  V = (9/11)\pi (3.5^{2} )(11)

 we get V = (9/11)(12.25)(11)π

                 =  110.25π in^{3}

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Match each function to its corresponding sequence.
givi [52]

The sequence and their functions are:

  • f(n) = f(n - 1) + 7 ⇒ 3, 10, 17, 24, 31.....
  • f(n) = f(n - 1) + 4n - 2 ⇒ 3, 9, 19, 33, 51.....
  • f(n) = 2[f(n - 1)] ⇒ 3, 6, 12, 24, 48.....

<h3>How to match the functions?</h3>

To do this, we simply set values for n and calculate the function values using the current value of n.

So, we have:

<u>Function 1: f(n) = f(n - 1) + 6n - 5 where f(1) = 3</u>

Let n = 2

f(2) = f(1) + 6(2) - 5 = 3 + 12 - 5 = 10

Let n = 3

f(3) = f(2) + 6(3) - 5 = 10 + 18 - 5 = 23

None of the sequence follows the pattern 3, 10, 23....

<u>Function 2: f(n) = f(n - 1) + 2n - 1 where f(1) = 3</u>

Let n = 2

f(2) = f(1) + 2(2) - 1 = 3 + 4 - 1 = 6

Let n = 3

f(3) = f(2) + 2(3) - 1 = 6 + 6 - 1 = 11

None of the sequence follows the pattern 3, 6, 11....

<u>Function 3: f(n) = f(n - 1) + 6 where f(1) = 3</u>

Let n = 2

f(2) = f(1) + 6 = 3 + 6 = 9

Let n = 3

f(3) = f(2) + 6 = 9 + 6 = 15

None of the sequence follows the pattern 3, 9, 15....

<u>Function 4: f(n) = f(n - 1) + 7 where f(1) = 3</u>

Let n = 2

f(2) = f(1) + 7 = 3 + 7 = 10

Let n = 3, 4 and 5

f(3) = f(2) + 7 = 10 + 7 = 17

f(4) = f(3) + 7 = 17 + 7 = 24

f(5) = f(4) + 7 = 24 + 7 = 31

So, we have:

f(n) = f(n - 1) + 7 ⇒ 3, 10, 17, 24, 31.....

<u>Function 5: f(n) = f(n - 1) + 4n - 2 where f(1) = 3</u>

Let n = 2

f(2) = f(1) + 4(2) - 2 = 3 + 8 - 2 = 9

Let n = 3, 4 and 5

f(3) = f(2) + 4(3) - 2 = 9 + 12 - 2 = 19

f(4) = f(3) + 4(4) - 2 = 19 + 16 - 2 = 33

f(5) = f(4) + 4(5) - 2 = 33 + 20 - 2 = 51

So, we have:

f(n) = f(n - 1) + 4n - 2 ⇒ 3, 9, 19, 33, 51.....

<u>Function 6: f(n) = 2[f(n - 1)] where f(1) = 3</u>

Let n = 2

f(2) = 2 * f(1) = 2 * 3 = 6

Let n = 3, 4 and 5

f(3) = 2 * f(2) = 2 * 6 = 12

f(4) = 2 * f(3) = 2 * 12 = 24

f(5) = 2 * f(4) = 2 * 24 = 48

So, we have:

f(n) = 2[f(n - 1)] ⇒ 3, 6, 12, 24, 48.....

Read more about sequence at:

brainly.com/question/6561461

#SPJ1

7 0
2 years ago
Which table represents y as a function of x?
alexira [117]

Answer:

The first one

Step-by-step explanation:

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What is the slope of the line shown below?
melisa1 [442]

Answer:

C. 2

Step-by-step explanation:

Gradient = \frac{change in y}{change in x}

Gradient = \frac{6}{3}

Gradient = 2

7 0
2 years ago
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A conical-shaped umbrella has a radius of 0.4 m and a height of 0.45 m. Calculate the amount of fabric needed to manufacture thi
GenaCL600 [577]

Answer:

0.76m²

Step-by-step explanation:

In the above question, we are given the following information.

Radius = 0.4m

Height = 0.45m

To solve this question, The umbrella is CONICAL in shape and it has no BASE, we would be finding the lateral surface area of a cone. Since we are given height and radius :

Lateral Surface Area of a cone =

πr√(h² + r²)

= π × 0.4√(0.45² + 0.4)

= 0.7566m²

≈ Approximately = 0.76m²

Therefore, the amount of fabric needed to manufacture this umbrella is 0.76m²

8 0
3 years ago
Help please i dont understand
kirza4 [7]
Vertical angles ate those that ate directly across from each other and share the same vertex. An example of this would be angles 5 and 7. These types of angles are also congruent, so angles 5 and 7 could be your congruent pair or another set of vertical angles like 1 and 3. A linear pair is two angles that together are a line. Basically, they are next ro each other (divided only by another vector) and are supplementary, adding up to 180 degrees. An example of this in the image is angles 1 and 2.
5 0
3 years ago
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