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andrey2020 [161]
3 years ago
15

Suppose two fractions are both less than 1. Can their sum be greater than 1? Greater than 2?

Mathematics
2 answers:
Rashid [163]3 years ago
8 0
Hi there!
Yes, if the two fractions are less than one, their sum can be greater than one. Take the example of 3/4 and 3/4. It is less than 1, but has a sum if 1 1/2.
However, their sum cannot be greater than 2. For that to happen, there would have to be a sum of at least 1 and 1, which are not fractions.

Hope this helps :)
Juliette [100K]3 years ago
4 0
Their sum can be greater than two. There is nothing that states that they couldn't be. All it states it that the two factions sums are less than 1. I hoped this helps 
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2c + 4d<br> C=8<br> D=-5<br> Please help
Dahasolnce [82]

Answer:

2c+4d

if c=8 and D=5,

2(8)+4(5)

16+20

=36

Step-by-step explanation:

5 0
2 years ago
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Assume each figure shown has the same orientation. Which figure is the image of square LMNP after a translation of
umka21 [38]

Figure 4 is the image of the square LMNP after the translation.

<u>Step-by-step explanation:</u>

Let us see the coordinates of the pre image LMNP as,

L (-3,1)

M(-1,1)

N(-1,-1)

P(-3,-1)

after translation of (x,y) → (x+5, y -3) the coordinates of the image obtained as,

L'(2,-2)

M'(4,-2)

N'(4,-4)

P'(2,-4) which matches the image 4.

8 0
3 years ago
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The number of cars at a dealership dropped from 64 to 48 after a weekend sale.
Mariana [72]

Answer:

25%

Step-by-step explanation:

{(whole- part)/whole}*100%

(64 -48)/64 *100%= 25%

8 0
3 years ago
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The sum is type answer as integer proper fraction or mixed number simplify answer
Evgesh-ka [11]

Answer:

9\dfrac{5}{6}

Step-by-step explanation:

5\dfrac{1}{6}+4\dfrac{2}{3}=\\\\5\dfrac{1}{6}+4\dfrac{4}{6}=\\\\9\dfrac{5}{6}

Hope this helps!

5 0
3 years ago
Suppose a normal distribution has a mean of 98 and a standard deviation of 6. What is P(x&lt; or = to 110)
dem82 [27]

Answer:

97.8%

Step-by-step explanation:

110 is 2 standard deviations above the mean (6+6 = 12)

12+98 = 110

Looking at the standard deviation curve

P(x< or = to 110)  = 1 - P(x>110)

We can find the probability that x>100 by adding  anything above 2 standard deviations above the curve.

P(x>110) = 2.1+.1 = 2.2%

P(x< or = to 110)  = 1 - P(x>110)

                                = 1- 2.2%

                                = 1- .022

                                  = .978

                               = 97.8 %

4 0
3 years ago
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