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andrey2020 [161]
3 years ago
15

Suppose two fractions are both less than 1. Can their sum be greater than 1? Greater than 2?

Mathematics
2 answers:
Rashid [163]3 years ago
8 0
Hi there!
Yes, if the two fractions are less than one, their sum can be greater than one. Take the example of 3/4 and 3/4. It is less than 1, but has a sum if 1 1/2.
However, their sum cannot be greater than 2. For that to happen, there would have to be a sum of at least 1 and 1, which are not fractions.

Hope this helps :)
Juliette [100K]3 years ago
4 0
Their sum can be greater than two. There is nothing that states that they couldn't be. All it states it that the two factions sums are less than 1. I hoped this helps 
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Which pair of angles are same side exterior angles?
In-s [12.5K]

Answer:

Exterior angles are the ones on the outside and same side means they sit on the same side of the bisector so your answer is 1 and 8

Step-by-step explanation:

6 0
3 years ago
Please Help I Will Mark Brainly . Thank You !
Ganezh [65]
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0.0801= 8.01×10^-2
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7 0
3 years ago
How do you do these two questions?
nignag [31]

Step-by-step explanation:

(a) ∫₋ₒₒ°° f(x) dx

We can split this into three integrals:

= ∫₋ₒₒ⁻¹ f(x) dx + ∫₋₁¹ f(x) dx + ∫₁°° f(x) dx

Since the function is even (symmetrical about the y-axis), we can further simplify this as:

= ∫₋₁¹ f(x) dx + 2 ∫₁°° f(x) dx

The first integral is finite, so it converges.

For the second integral, we can use comparison test.

g(x) = e^(-½ x) is greater than f(x) = e^(-½ x²) for all x greater than 1.

We can show that g(x) converges:

∫₁°° e^(-½ x) dx = -2 e^(-½ x) |₁°° = -2 e^(-∞) − -2 e^(-½) = 0 + 2e^(-½).

Therefore, the smaller function f(x) also converges.

(b) The width of the intervals is:

Δx = (3 − -3) / 6 = 1

Evaluating the function at the beginning and end of each interval:

f(-3) = e^(-9/2)

f(-2) = e^(-2)

f(-1) = e^(-1/2)

f(0) = 1

f(1) = e^(-1/2)

f(2) = e^(-2)

f(3) = e^(-9/2)

Apply Simpson's rule:

S = Δx/3 [f(-3) + 4f(-2) + 2f(-1) + 4f(0) + 2f(1) + 4f(2) + f(3)]

S ≈ 2.5103

5 0
3 years ago
Which statement is true? A.Two angles can be complementary and equal. B.Two angles cannot be equal if they are complementary. C.
o-na [289]
A because complementary angles means 2 angles that add together to equal 90 degrees and it's possible for both angles to be 45.
3 0
3 years ago
Choose the equivalent system of linear equations that will produce the same solution as the one given below.
Amanda [17]
<h2>Greetings!</h2>

Answer:

Option 4

Step-by-step explanation:

Firstly, we need to make the two x's or the two y numbers the same. Lets multiply the second equation by 2:

(2x + 3y = 5 ) * 2 =

4x + 6y = 10

Now, subtract the second equation from the first one:

(4x - y = -11) - (4x + 6y = 10)

4x - 4x = 0

-y - 6y = -7y

-11 - 10 = -21

-7y = -21

Divide both sides by -7:

y = 3

Plug 3 into the first equation as y:

4x - 3 = -11

4x = -11 + 3

4x = -8

x = -2

So x = -2 and y = 3. We need to find one of the options that equals this.


<h3>Option  1)</h3>

-4x - 9y = -21

-10y = -30

40x - 90y = -210

-90y = -270

40x - 0 = 40x

-90y - - 90y = -90 + 90 = 0y

-210 - -270 = -210 + 270 = 60

40x = 60

x = 1.5

We already know this isn't equivalent because the x value is not the x value of the given equation.


<h3>Option 2) </h3>

4x + 3y = 5

2y = -6

_______

8x + 6y = 10

6y = -18

8x - 0 = 8x

6y - 6y = 0

10 - -18 = 10 + 18 = 28

8x = 28

x = 3.5

So we know this isn't equivalent because again, the x value isn't the same as the given equation.


<h3>Option 3</h3>

7x - 3y = -11

9x = -6

-----------

63x - 27y = -99

63x = -42

----------------

63x - 63x = 0

-27y - 0 = -27y

-99 - - 42 = -99 + 42 = -57

-27y = -57

-9y = -19

9y = 19

y = 19/9

So we know this one isn't equivalent as the y value isn't the same as the given equation.


<h3>Option 4</h3>

12x - 3y = -33

14x = -28

x = -28/14 = -2

12(-2) - 3y = -33

-24 - 3y = -33

-3y = -33 + 24

-3y = -9

y = 9/3

y = 3

So x = -2 and y = -3 which is the same as the first equation.


<h2>Hope this helps!</h2>
3 0
3 years ago
Read 2 more answers
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