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Mrac [35]
3 years ago
15

5. Leyla will roll a number cube 1-4 and flip a coin. The coin can land on heads or tails. If Leyla rolls the number cube once a

nd flips the coin once, which list contains only the outcomes in which the number cube land on a number greater than 3?
Mathematics
1 answer:
mario62 [17]3 years ago
3 0

Answer:

{4H, 4T}

Step-by-step explanation:

The list that contains only the outcomes where the number cube is more than 3 is given below:

Sample space is

= {1,2,3,4}

The results more than 3 is

S = {3}

After this, the sample space i.e. C when the coin is fippled is

C = {H, T}

Here H denotes the Head

T denotes Tail

So, the outcomes would be

= {4} + {H,T}

= {4H, 4T}

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The slope of the line containing the points (6, 4) and (-5, 3) is:<br><br> 1<br> -1<br> 1/11
julsineya [31]

Answer:

1/11

Step-by-step explanation:

(6, 4) and (-5, 3)

Slope:

m=(y2-y1)/(x2-x1)

m=(3-4)/(-5-6)

m= (-1)/(-11)

m = 1/11

3 0
3 years ago
Cycle City charges an initial price of $15 plus $0.75 per hour for bike rentals, which is represented by the expression 15 + 0.7
daser333 [38]

Answer:

18

H = cost per hour

15 = the rental price

0.75H = the hourly rental

Step-by-step explanation:

H = Cost per Hours

H = 15 + 0.75H

H = 15 + 0.75 * 4

H = 15 + 3

H = 18

5 0
2 years ago
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HELP PLZ ASAP!!! I will attach the work below once this is posted.
telo118 [61]
Well what exactly do you need help with?
3 0
3 years ago
An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.
andrey2020 [161]

Answer:

The probability that A selects the first red ball is 0.5833.

Step-by-step explanation:

Given : An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

To find : What is the probability that A selects the first red ball?

Solution :

A wins if the first red ball is drawn 1st,3rd,5th or 7th.

A red ball drawn first, there are E(1)= ^9C_2 places in which the other 2 red balls can be placed.

A red ball drawn third, there are E(3)= ^7C_2 places in which the other 2 red balls can be placed.

A red ball drawn fifth, there are E(5)= ^5C_2 places in which the other 2 red balls can be placed.

A red ball drawn seventh, there are E(7)= ^3C_2 places in which the other 2 red balls can be placed.

The total number of total event is S= ^{10}C_3

The probability that A selects the first red ball is

P(A \text{wins})=\frac{(^9C_2)+(^7C_2)+(^5C_2)+(^3C_2)}{^{10}C_3}

P(A \text{wins})=\frac{36+21+10+3}{120}

P(A \text{wins})=\frac{70}{120}

P(A \text{wins})=0.5833

6 0
3 years ago
Math problem I need help on
JulijaS [17]

Answer:I think the answer is

1. x=8

Step-by-step explanation:

1. X=8

2. X=1⅓

3. 0x=-12

4. -8x=0

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8 0
3 years ago
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