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joja [24]
3 years ago
6

A merchant mixed 10 lb of a cinnamon tea with 2 lb of spice tea. The 12-pound mixture cost $13. A second mixture included 16 lb

of the cinnamon tea and 8 lb of the spice tea. The 24-pound mixture cost $28. Find the cost per pound of the cinnamon tea and of the spice tea.
Mathematics
1 answer:
Sonja [21]3 years ago
3 0

Step-by-step explanation:

Let's say c is the price of cinnamon tea, and s is the price of spice tea.

10c + 2s = 13

16c + 8s = 28

Divide the second equation by 4:

4c + 2s = 7

Subtract from the first equation:

6c = 6

c = 1

Use any equation to find s.

s = 1.5

Therefore, the cinnamon tea costs $1 per pound and the spice tea costs $1.50 per pound.

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Answer:

a_{n}= 1+2n and 63

Step-by-step explanation:

the question belongs to arithmetic sequence and a_{n} can be determined by the formula

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Let " a_{n} " represents the number of band members in the nth row

and 'd' represents the common difference.( as stated each row  has 2 more band members than the row before it)

therefore, d=2

'a1' represents first row that has three members. So, a1 = 3

->Rule for nth term will be:

a_{n}= 3 + 2(n-1)

a_{n}= 3 + 2n -2

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Let S_{n} represent total number in n rows

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=>S_{7} = 7/2 (3 + 15)

S_{7} = 63

The total number of band members are 63

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