Answer:
Null hypothesis is: U1 - U2 ≤ 0
Alternative hypothesis is U1 - U2 > 0
Step-by-step explanation:
The question involves a comparison of the two types of training given to the salespeople. The requirement is to set up the hypothesis that type A training leads to higher mean weakly sales compared to type B training.
Let U1 = mean sales by type A trainees
Let U2 = mean sales by type B trainees
Therefore, the null hypothesis (H0) is: U1 - U2 ≤ 0
This implies that type A training does not result in higher mean weekly sales than type B training.
The alternative hypothesis (H1) is: U1 - U2 > 0
This implies that type A training indeed results in higher mean weekly sales than type B training.
Answer:
29.411 % of the result is true.
Step-by-step explanation:
This test's sensitivity is low.
Suppose we have 5 drug users and 85% of the test is accurate meaning that 5* 0.85= 4.25 people are drug users which is true.
But if work for the non users than 5% people being drug users means 95 people are non drug users out of the hundred.
And 85 % accuracy would give 95* 0.85= 80.75 which is very high.
And out of the 80.75 * 15%= 12.11 only 12 are positive .
The results give us 5 out of 17 true possibilities
or 5/17 *100= 29.411 % of the result is true.
Answer:
5n
Step-by-step explanation:
Summarizing what we know:
Casey has n nickels, and Meghan 4 times as many: 4n
Then the total number of nickets these two people have is n + 4n, or 5n.
" · " - product
" - " - difference
13 · (8 - (-10)) = 13 · (8 + 10) = 13 · 18 = 234
