The answer is the 3rd one
The answer would be 8x^4 + 16x^3y - 48x^2y^2
In order to find this, multiply 8x^2 by each term individually.
8x^2 * x^2 = 8x^4
8x^2 * 2xy = 16 x^3y
8x^2 * -6y^2 = -48x^2y^2
Now you can put them all in a row.
8x^4 + 16x^3y - 48x^2y^2
<h3>
Answer: D) Cannot be determined</h3>
Explanation:
Choice A isn't the answer because we don't know anything about the angles, so we can't use the AA (angle angle) Similarity theorem.
Choice B isn't the answer because we don't have info about all three pairs of sides (we only have two pairs of sides).
Choice C isn't the answer in a similar way choice A isn't either. We don't know anything about the angles, so we can't use the "A" in "SAS".
Choice D is the only thing left. It turns out we don't have enough info to be able to determine if the triangles are similar or not.
The answer should be 26 hours
Answer:
![\int_{-\infty}^0 5 e^{60x} dx = \frac{1}{12}[e^0 -0]= \frac{1}{12}](https://tex.z-dn.net/?f=%20%5Cint_%7B-%5Cinfty%7D%5E0%205%20e%5E%7B60x%7D%20dx%20%3D%20%5Cfrac%7B1%7D%7B12%7D%5Be%5E0%20-0%5D%3D%20%5Cfrac%7B1%7D%7B12%7D)
Step-by-step explanation:
Assuming this integral:
We can do this as the first step:
Now we can solve the integral and we got:
![\int_{-\infty}^0 5 e^{60x} dx = \frac{e^{60x}}{12}\Big|_{-\infty}^0 = \frac{1}{12} [e^{60*0} -e^{-\infty}]](https://tex.z-dn.net/?f=%20%5Cint_%7B-%5Cinfty%7D%5E0%205%20e%5E%7B60x%7D%20dx%20%3D%20%5Cfrac%7Be%5E%7B60x%7D%7D%7B12%7D%5CBig%7C_%7B-%5Cinfty%7D%5E0%20%3D%20%5Cfrac%7B1%7D%7B12%7D%20%5Be%5E%7B60%2A0%7D%20-e%5E%7B-%5Cinfty%7D%5D)
So then we see that the integral on this case converges amd the values is 1/12 on this case.
