Answer: 1 1/2
Explanation: the first number of the division problem stays the same but you flip the second fraction witch is 1/2 then that will be 2/1 then change the division symbol into a multiplication symbol and 3/4 times 2/1 and that equals6/4 and 6/4 is divisible by two so you divide 6/4 x 2. That equals 3/2 and you had to make that a mixed number so you divide two and 33 on the inside of the house and two on the outside. Two goes into threewants and when is your whole number and your remainder is one and one is your numerator and two is your denominator. You might understand it better if you see my work which a photo of it is down below.
Answer:
42 units squared
Step-by-step explanation:
break it up into smaller shapes. if you split the big shape at y = 2 and at y=-2, you'll get two triangles and one rectangle.
so the area of the rectangle = l x w
= 4 x 7
= 28
the area of the triangle is ( l x w )/2
= (7 x 2)/2
= 7
the other triangle is the same too
so the area of that is also 7.
now add all areas,
7+7+28 = 42
Answer:
Step-by-step explanation:
Area of the figure = Area of semicircle + area of rectangle
Area of semicircle:
d = 14 mm
r = 14/2 = 7 mm
Area = (1/2)πr²

=11 *7
= 77 mm²
Area of rectangle:
length = 14 mm
Width = 10 mm
Area = length *width
= 14 * 10
= 140 mm²
Area of the figure = 77 + 140 = 217 mm²
Answer:
The required prove is shown below.
Step-by-step explanation:
Consider the provided statement.
The required figure is shown below:
Statement Reasons
PQ ≅ TQ; UQ ≅ QS Given
PQ = TQ, UQ = QS Definition of Congruence
PQ + QS = PS; TQ+QU = TU Segment Addition Postulate
TQ + QS = PS Substitution (PQ = TQ)
TQ + QS = TU Substitution (QU = QS)
PS = TU Transitive Property
Prove: PS ≅TU Definition of Congruence
Hence, the required prove is shown above.
Answer:24
Step-by-step explanation: