All categories

3 years ago

If a cubic container has a side length of 50.0cm, what is the volume in liter?

Mathematics

1 answer:

zimovet [89]3 years ago

3 0

Answer:

The answer is

<h2>125 litres</h2>

Step-by-step explanation:

To find the volume in liter we must first find the volume in cm³

Since the container is cubic

Volume = l³

where l is the length of one side

From the question

l = 50.0 cm

Volume = 50³

= 125000 cm³

Next we use the conversion

1cm³ = 0.001 L

If 1 cm³ = 0.001 L

Then 125,000 cm³ = 125,000 × 0.001 L

We have the final answer as

<h3>125 litres</h3>

Hope this helps you

You might be interested in

Select all statements

Ilia_Sergeevich [38]

Step-by-step explanation:

(A) squares are congruant .

(B) rectangle having equal length of same side is congruent.

(C)it is true because it have same side length are equal.

(D)it is true because same same side length are equal.

(E) it is truebecause same side length are equal.

8 0

3 years ago

PLEASE HELP!!! Number 2, and 4 please!! (YOU HAVE TO FIND THE SURFACE AREA OF THE PRISM)

Elenna [48]

The answer for 2 is 192. The answer for 4 is 672.

8 0

3 years ago

HELPP PLSSS!!! When factoring a number, you can use _[blank 1] as a shortcut. For example, you can tell if 5 is a factor of a nu

Andru [333]

Answer:

blank 1: divisibility rules

blank 2: its last digit is 0 or 5

3 0

3 years ago

A spring has a natural length of 20 cm. If a 30-N force is required to keep it stretched to a length of 38 cm, how much work W i

sergeinik [125]

Replace your arnswer to 64

5 0

3 years ago

Simplify.<br><br> 1/4 (1 - 2/3)² + 1/3.<br><br> The answer must be a simplified fraction.

loris [4]

Answer:

$\large\boxed{\dfrac{13}{36}}$

Step-by-step explanation:

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

---------------------------------------------------------------------------

$\dfrac{1}{4}\left(1-\dfrac{2}{3}\right)^2+\dfrac{1}{3}=\dfrac{1}{4}\left(\dfrac{3}{3}-\dfrac{2}{3}\right)^2+\dfrac{1}{3}=\dfrac{1}{4}\left(\dfrac{3-2}{3}\right)^2+\dfrac{1}{3}\\\\=\dfrac{1}{4}\left(\dfrac{1}{3}\right)^2+\dfrac{1}{3}=\dfrac{1}{4}\cdot\dfrac{1^2}{3^2}+\dfrac{1}{3}=\dfrac{1}{4}\cdot\dfrac{1}{9}+\dfrac{1}{3}=\dfrac{1}{36}+\dfrac{1}{3}\qquad(*)\\\\\text{the common denominator is}\ 36.\\\\36=3\cdot12\to\dfrac{1}{3}=\dfrac{1\cdot12}{3\cdot12}=\dfrac{12}{36}\\\\(*)\qquad=\dfrac{1}{36}+\dfrac{12}{36}=\dfrac{1+12}{36}=\dfrac{13}{36}$

4 0

3 years ago