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AnnyKZ [126]
4 years ago
9

2x (z-1) + 8x helpppp

Mathematics
1 answer:
miv72 [106K]4 years ago
6 0
2x(z-1)+8x
2xz-2x+8x
2xz+6x
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Answer:

step 2

Step-by-step explanation:

The student first made an error in the step 2.

Because if we simplify the equation A in step 1, we should distribute the right side of the equation following the rule a(b-c) = a*b +a*(-c)

So, it would be

–7y = (-7)*(16)+(-7)*(-2z)

=> -7y = -112 + 14z

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Answer:

D.

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Step-by-step explanation:

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x² × 2x = 16 × 8 = 128
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Which are the solutions of x2 = –11x + 4? StartFraction negative 11 minus StartRoot 137 EndRoot Over 2 EndFraction comma StartFr
Marysya12 [62]

Answer:

x_1=-\frac{11}{2}-\frac{\sqrt{137} }{2}\\\\x_2=-\frac{11}{2}+\frac{\sqrt{137} }{2}

Step-by-step explanation:

Given the following quadratic equation:

x^2 = -11x + 4

The steps to solve it are:

1. Move the terms to one side of the equation:

x^2+11x- 4=0

2. Apply the Quadratic formula x=\frac{-b\±\sqrt{b^2-4ac} }{2a}.

In this case we can identify that:

a=1\\b=11\\c=-4

Then, substituting these values into the Quadratic formula we get the following solutions:

x=\frac{-11\±\sqrt{11^2-4(1)(-4)} }{2(1)}

x_1=-\frac{11}{2}-\frac{\sqrt{137} }{2}\\\\x_2=-\frac{11}{2}+\frac{\sqrt{137} }{2}

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4 years ago
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