The partial products would be 10 multiply 40, 10 multiply 3, 7 multiply 40, and 7 multiply 3.
Let, the first (smaller) number = x
Larger number = 8x
Then, 8x - x = 70
7x = 70
x = 70/7
x = 10
& 8(10) = 80
In short, Your Numbers would be, 10 & 80
Hope this helps!
Answer:
4^3x=4^(4x+4)
Step-by-step explanation:
You can eliminate the first 2 options since those don’t make sense already, and the last option changed 64 to 2^6 which is correct, but when they changed the other side. They should have multiplied 8 to both x and 1 which would have made the whole term 2^(8x+8) and not 2^(8x+1). Left with the third option, 4 to the power of 3 is 64 so the left side makes sense, 4^3x=64^x, on the right side, 4^4 equals 256, so the whole exponent should multiply by 4 so from 256^(x+1) you get 4^4(x+1) giving 4^(4x+4) making the third choice the right answer.
Hello from MrBillDoesMath!
Answer:
x + 9 and (x + ( i - 7)) are factors
Discussion:
If f(x) has roots -9 and 7-i then
f(x) = g(x)(x - (-9)) (x - (7-i)) ( g(x) is a polynomial of degree less than f(x))
That is, x + 9 and (x + ( i - 7)) are factors of f(x)
BTW: if the coefficients of f(x) are real (not stated in the Question) then the conjugate of 7-i, i.e. 7 + i, is also be a root.
Thank you,
MrB
